<h3>
I'll teach you how to solve f(x)=0x63 - 52x – 96</h3>
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f(x)=0x^3 - 52x – 96
Apply rule:
0 * a= 0
0-52x-96
Group like terms:
-52x+0-96
Add/subtract the numbers:
0-96= -96
-52x-96
Your Answer Is -52x-96
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Answer:
x = 12
Step-by-step explanation:
Remark
These two angles are corresponding angles and as such, they are equal.
Equation
8x+ 36 = 5x + 72
Solution
Subtract 5x from both sides
8x - 5x + 36 = 5x - 5x + 72 Combine like terms.
3x + 36 = 72 Subtract 36 from both sides
3x + 36 - 36 = 72 - 36 Collect like terms
3x = 36 Divide by 3
3x/3 = 36/3 Divide
x = 12 Answer
Y + 3 = 1.2(x - 0)
y + 3 = 1.2x - 0
y = 1.2x - 3
Answer:
13. 5 minutes
Step-by-step explanation:
This is a simple proportion problem. Make two fractions where one item is always on the top and the other on the bottom.
![\frac{3 min}{128 words} = \frac{x min}{ 576 words}](https://tex.z-dn.net/?f=%5Cfrac%7B3%20min%7D%7B128%20words%7D%20%3D%20%5Cfrac%7Bx%20min%7D%7B%20576%20words%7D)
Now, cross multiply (multiply the two numbers diagonal from each other and divide the diagonal with the x value)
576 x 3 = 1, 728
1, 728 / 128 = 13.5
<span>Assuming that the particle is the 3rd
particle, we know that it’s location must be beyond q2; it cannot be between q1
and q2 since both fields point the similar way in the between region (due to
attraction). Choosing an arbitrary value of 1 for L, we get </span>
<span>
k q1 / d^2 = - k q2 / (d-1)^2 </span>
Rearranging to calculate for d:
<span> (d-1)^2/d^2 = -q2/q1 = 0.4 </span><span>
<span> d^2-2d+1 = 0.4d^2 </span>
0.6d^2-2d+1 = 0
d = 2.72075922005613
d = 0.612574113277207 </span>
<span>
We pick the value that is > q2 hence,</span>
d = 2.72075922005613*L
<span>d = 2.72*L</span>