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maw [93]
2 years ago
14

What type of association and correlation are shown by the scatterplot? On a graph, points are grouped closely together and incre

ase. linear association, positive correlation linear association, negative correlation nonlinear association, strong correlation nonlinear association, weak correlation
Mathematics
2 answers:
Oliga [24]2 years ago
8 0

Answer:

Linear association and positive correlation, or a.

Step-by-step explanation:

The dots appear to go up, giving the positive appearance, and the dots are in a linear shape, hence the linear association.

Annette [7]2 years ago
6 0

Answer:

A) Linear association, positive correlation

Step-by-step explanation:

I took the test lol >w<

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Explain how you can find 4 times 754 using two different methods.
ludmilkaskok [199]
Method 1:

4(754)

=4(700+50+4)

=2800 + 200 + 16

=3000+16

=3016

-----------------

Method 2:

4(754)

=4(250+250+250+4)

=1000+1000+1000+16

=3016
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Cheeseburgers to go has advertised for counter help. If you take the job, you will be working 18 hours a week for $75.20 per wee
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Divide the weekly amount by the number of hours worked:

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Rounded to the nearest cent = $4.18 per hour.

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Question 6 of 9 (3•8) • 1 = 3 • (8.1) O A. True B. False​
olga nikolaevna [1]

Answer:

No, (false). The question I assume was: (3*8)*1=3*(8.1)

Step-by-step explanation:

1. Multiple: 3 * 8 = 24

2. Multiple: <em><u>The result of step No. 1:</u></em> * 1 = 24 * 1 = 24

3. Conversion a decimal number to a fraction: 8.1 = \frac{81}{10} = \frac{81}{10}

   a) Write down the decimal 8.1 divided by 1: 8.1 = \frac{81}{1}

   b) Multiply both top and bottom by 10 for every number after the

       decimal point. (For example, if there are two numbers after the decimal

       point, then use 100, if there are three then use 1000, etc.)

       \frac{8.1}{1} = \frac{81}{10}

   Note: \frac{81}{10} is called a decimal fraction.

   c) Simplify and reduce the fraction

       \frac{81}{10} = \frac{81*1}{10*1} = \frac{81}{10}

4. Multiple: 3 * 8.1 = \frac{3*81}{1*10} = \frac{243}{10}

   Multiply both numerators and denominators. Result fraction keep to lowest

   possible denominator GCD(243, 10) = 1. In the next intermediate step the

   fraction result cannot be further simplified by canceling.

   In words - three multiplied by eighty-one tenths = two hundred forty-three

   tenths.

5. Compare: <em><u>The result of step No. 2 </u></em>vs <em><u>The result of step No. 4</u></em>: = 24 vs \frac{243}{10} = \frac{24}{1} vs \frac{243}{10} = \frac{24*10}{1*10} vs \frac{243}{10} = \frac{240}{10} vs\frac{243}{10} = 240 vs 243 = No

5 0
3 years ago
Evaluate x - 7 for x = 14.
Aleksandr-060686 [28]

Answer:

x=21

Step-by-step explanation:

x-7=14

add  7 to both sides

x=21

8 0
3 years ago
Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x2/3 + y2/3 = 4 (−3 3 , 1)
vovikov84 [41]

Answer with Step-by-step explanation:

We are given that an equation of curve

x^{\frac{2}{3}}+y^{\frac{2}{3}}=4

We have to find the equation of tangent line to the given curve at point (-3\sqrt3,1)

By using implicit differentiation, differentiate w.r.t x

\frac{2}{3}x^{-\frac{1}{3}}+\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=0

Using formula :\frac{dx^n}{dx}=nx^{n-1}

\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=-\frac{2}{3}x^{-\frac{1}{3}}

\frac{dy}{dx}=\frac{-\frac{2}{3}x^{-\frac{1}{3}}}{\frac{2}{3}y^{-\frac{1}{3}}}

\frac{dy}{dx}=-\frac{x^{-\frac{1}{3}}}{y^{-\frac{1}{3}}}

Substitute the value x=-3\sqrt3,y=1

Then, we get

\frac{dy}{dx}=-\frac{(-3\sqrt3)^{-\frac{1}{3}}}{1}

\frac{dy}{dx}=-(-3^{\frac{3}{2}})^{-\frac{1}{3}}=-\frac{1}{-(3)^{\frac{3}{2}\times \frac{1}{3}}}=\frac{1}{\sqrt3}

Slope of tangent=m=\frac{1}{\sqrt3}

Equation of tangent line with slope m and passing through the point (x_1,y_1) is given by

y-y_1=m(x-x_1)

Substitute the values then we get

The equation of tangent line is given by

y-1=\frac{1}{\sqrt3}(x+3\sqrt3)

y-1=\frac{x}{\sqrt3}+3

y=\frac{x}{\sqrt3}+3+1

y=\frac{x}{\sqrt3}+4

This is required equation of tangent line to the given curve at given point.

8 0
3 years ago
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