Given that ∠B ≅ ∠C.
to prove that the sides AB = AC
This can be done by the method of contradiction.
If possible let AB =AC
Then either AB>AC or AB<AC
Case i: If AB>AC, then by triangle axiom, Angle C > angle B.
But since angle C = angle B, we get AB cannot be greater than AC
Case ii: If AB<AC, then by triangle axiom, Angle C < angle B.
But since angle C = angle B, we get AB cannot be less than AC
Conclusion:
Since AB cannot be greater than AC nor less than AC, we have only one possibility. that is AB =AC
Hence if angle B = angle C it follows that
AB = AC, and AB ≅ AC.
Answer:
It is B, 7 points.
Step-by-step explanation:
You can start from the point (8,2) and then you go up 7 points to reach the point (8,9) which is 7 points.
Find the factors of -3:
1,-3 and 3,-1
which ever adds up to 1 multiplied by 2
the answer is (2x+3)(x-1)
hope this helps
Let the integers be x - 1, x and x + 1, then
x - 1 + x + x + 1 = -42
3x = -42
x = -42/3 = -14
The three consectutive integers are -15, -14 and -13