Hello, I need some help with this. I hate this SSS, SAS, AAS, stuff.

60 POINTS PLEASE HURRY!!

g100num [7]

Answer:

A. Rashid solved the problem correctly.

7 0

3 years ago

Read 2 more answers

What is the factorization of 84

Vladimir79 [104]

Answer:

2×2×3×7

Step-by-step explanation:

84 is even, so divisible by 2. 84 = 2×42

42 is even, so divisible by 2. 82 = 2×2×21

21 has a sum of digits of 3, so is divisible by 3. 84 = 2×2×3×7

4 0

3 years ago

Which represents the reflection of f(x)=sqrt x over the y axis

zloy xaker [14]

reflection of $f(x)=\sqrt{x}$ over the y axis we get $g(x)=\sqrt{-x}$

Step-by-step explanation:

We need to find the reflection of f(x)=sqrt x over the y axis

So, reflection over y- axis

If the function f(x) is transformed over y-axis then the new function g(x) will be $g(x)= f(-x)$

So, finding reflection of $f(x)=\sqrt{x}$ over the y axis we get:

$g(x)=\sqrt{-x}$

So, reflection of $f(x)=\sqrt{x}$ over the y axis we get $g(x)=\sqrt{-x}$

Keywords: Transformations

Learn more about Transformations at:

#learnwithBrainly

6 0

3 years ago

The speeds of vehicles traveling on a highway are normally distributed with an unkown population mean and standard deviation. A

Maksim231197 [3]

Answer:

The 90% confidence interval would be given by (60.09;69.91)

We are 90% confident that the true mean for the speeds of vehicles traveling on a highway is between 60.09 and 69.91 miles per hour.

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X =65$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=9 represent the sample standard deviation

n=11 represent the sample size

2) Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=11-1=10$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,10)".And we see that $t_{\alpha/2}=1.81$