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Zanzabum
3 years ago
10

18m + –5m + 8m + 6 = –15 solve for m

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
5 0

Answer: M= -1

Step-by-step explanation:

18m + -5m + 8m= -21 (combine like terms)

21m= -21 (bring the positive 21 over to the other side by dividing)

m = -1

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Step-by-step explanation:

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2 years ago
Write a real life scenario that can be represented by the integer –55.
Lynna [10]

Comparing the temperature of a coolant before and after use in a machining process.

Step-by-step explanation:

The temperature of a coolant in the polar region was found to be modeled by the equation t=(8x-55)° where t is the final fluid temperature after being used for cooling ,x is the time the fluid is applied on the cutting edge and -55 is the normal temperature of the fluids used for cooling processes in a machine garage.

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7 0
3 years ago
A number to the fourth power decreased by 600 is 25
muminat

Answer:

x=5

Step-by-step explanation:

A number to the fourth power decreased by 600 is 25

x^4-600=25

Step 1- Add To Both Sides

x^4-600=25

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A number to the fourth power decreased by 600 is 25

Step 2- Find square root

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4 0
4 years ago
Read 2 more answers
How many ways are there to travel in xyz space from the origin (0, 0, 0) to the point (4, 3, 5) by taking steps one unit in the
Virty [35]
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5 0
3 years ago
I need to find the least common denominator of x+2/x^2+2x-3 , x-7/x^2+5x+6
grin007 [14]

Answer:

(x + 3)(x - 1)(x + 2)  

Step-by-step explanation:

The fractions are:  

\dfrac{x + 2}{x^{2} + 2x - 3} \text{ and } \dfrac{x - 7}{x^{2} + 5x + 6}

Factor each denominator  

x^{2} + 2x - 3 = (x + 3)(x - 1)\\x^{2} + 5x + 6 = (x + 3)(x + 2)

We must find the least common multiple of the denominators.  We take the maximum power of each separate factor.

      Factors of first fraction = (x + 3) × (x - 1)

Factors of second fraction = (x + 3)             × (x + 2)

                                   LCM = (x + 3)(x - 1)(x + 2)

The lowest common denominator of the two fractions is (x + 3)(x - 1) (x + 2).

4 0
3 years ago
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