Answer:
Step-by-step explanation:
The length of a chalkboard, l = 1.7
The width of a chalkboard, b = 0.9 m
We need to find the area of the chalkboard. The formula for the area of a rectangle is given by :
So, the area of the chalkboard is equal to 
.
Answer:
125
Step-by-step explanation:
1 x 1 x 1 = 1
5 x 5 x 5 = 125
125 / 1 = 125
125 is your answer
Answer:
?= 63.15789474%
Step-by-step explanation:
Use cross multiply
Set ?=x
Answer:
x=0.9
Step-by-step explanation:
(ask me if u want it)
1)
LHS = cot(a/2) - tan(a/2)
= (1 - tan^2(a/2))/tan(a/2)
= (2-sec^2(a/2))/tan(a/2)
= 2cot(a/2) - cosec(a/2)sec(a/2)
= 2(1+cos(a))/sin(a) - 1/(cos(a/2)sin(a/2))
= 2 (1+cos(a))/sin(a) - 2/sin(a)) (product to sums)
= 2[(1+cos(a) -1)/sin(a)]
=2cot a
= RHS
2.
LHS = cot(b/2) + tan(b/2)
= [1 + tan^2(b/2)]/tan(b/2)
= sec^2(b/2)/tan(b/2)
= 1/sin(b/2)cos(b/2)
using product to sums
= 2/sin(b)
= 2cosec(b)
= RHS
