Answer:
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Answer:
A= 20%
G= 30%
T= 20%
C= 30%
Explanation:
Recall that the sum of all nitrogenous bases in the DNA nucleotide is equal to 100%. And specific base pairings of Adenine to Thymine (A=T), and Cytosine to Guanine (C=G) must be equal.
So, the percentage of Adenine equal thymine, and that of cytosine equals guanine.
Now, A + T + C + G = 100%
So, if Adenine makes up 20% of the DNA nucleotides, Thymine is also 20%.
Then, 20% + 20% + C + G = 100%
40% + C + G = 100%
C + G = 100% - 40% = 60%
So, divide 60% by 2 to obtain the individual percentage of cytosine and guanine. Each will take 30%
Finally, A= 20%; G= 30%; T= 20%; C= 30%
Answer and Explanation:
<u>Cross:</u> aa Bb dd Ee x AA bb Dd Ee
We can calculate the probability of getting heterozygous individuals in the progeny by using the <u>product rule</u>. Assuming that these four genes <u>assort independently</u> (<em>events that occur independently from each other</em>), we can infer that the F1 will have the next genotypic proportions for each gene:
1) aa x AA
F1) 4/4=1 Aa
2) Bb x bb
F1) ½ bb
½ Bb
3) dd x Dd
F1) ½ dd
½ Dd
4) Ee x Ee
F1) ¼ EE
2/4 = ½ Ee
¼ ee
So, to know what the probability is that the F1 of being heterozygous for all loci, we must multiply the respective individual probabilities of getting a heterozygous genotype, like this:
1 Aa x ½ Bb x ½ Dd x ½ Ee = 1/8 AaBbDdEe
