Domain: The set of possible values of x
Range: The set of possible values of y
Zeros: The x-intercepts (what value of x is on the x-axis)
Discontinuities: Where the graph stops (and restarts somewhere else)
Asymptotes: The graph cannot cross this line (vertical, horizontal, oblique)
Answer:
y = -3/1x + 2
Step-by-step explanation:
1. Find the slope
The points I will use are (-1,5) and (0,2), where x1 = -1, y1 = 5, x2 =0, and y2 =2.
y2-y1/x2-x1
2-5/0-(-1) = -3/1
2. Find the y-intercepy
y = mx + b
You can use any x or y point. I'll use (-1,5)
m= slope, which is -3/1
5= -3/1(-1) +b
5= 3 + b
Subtract 3 from 5 and 3 to get 2=b.
3. Rewrite in slope-intercept form
y = -3/1x + 2
Please give us the options<span />
Answer:
Numbers =(6,-2 )
Step-by step explanation:
Given
the sum of two numbers is four and the sum of their squares minus three times their product is 76,
Let the first term =X
Second term will be=4-x
So
X^2+(4-x)^2-3x(4-x)=76
x^2+16+x^2-8x-12x+3x^2=76
5x^2-20x+16=76
5x^2-20x-60=0
5(x^2-4x-12)=0
So x^2-4x-12=0
x^2-(6-2)x-12=0
x^2-6x+2x-12=0
X(x-6)+2(x-6)=0
(X-6)(X+2)=0
X=6,-2
Let X=6 and -2 then numbers will be 6 and (4-6)=-2
