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2 years ago

Help fast will give brainlist

Mathematics

1 answer:

Scrat [10]2 years ago

4 0

Answer:

the picture is black send another one

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MATTHEW HAS A BAG OF 100 PIECES OF CANDY. HE NEEDS TO SPLIT THE BAG BETWEEN HIS CLASSMATES IN HIS AM AND PM CLASS. HE HAS 20 STU

DiKsa [7]

Answer: They can recieve about 2.

Exact answer: 2.5

Step-by-step explanation:

If you divded 100 by 40, you get 2.5

Since there are 20 students in each AM and PM classes. you add 20 and 20, which is 40, then you divided by 100 which is 2.5

4 0

3 years ago

7. Which pair shows equivalent expressions? A. 3(x+2) = 3x + 6 B. 3x + 2x = x²(x + 2) C. 3x + 2 = 3(x + 2) D. -3(2 + x) = -6x -

Sergio039 [100]

C has equivalent expressions I think

8 0

2 years ago

5. Naomi was watching a game show where

Solnce55 [7]

Answer:

C) 50

Step-by-step explanation:

This is because -10 x 5 = -50 and if you have 20 points to start with, you just do 20-(-30)=20 and two minuses make a plus so it is 20 + 30 which is 50.

8 0

3 years ago

Math problems solve

Stolb23 [73]

Number???what do you want?

6 0

3 years ago

In the past, 21% of all homes with a stay-at-home parent, the father is the stay-at-home parent. An independent research firm ha

Afina-wow [57]

Answer:

A sample size of 79 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$\pi = 0.21$

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

What sample size is needed if the research firm's goal is to estimate the current proportion of homes with a stay-at-home parent in which the father is the stay-at-home parent with a margin of error of 0.09?

A sample size of n is needed.

n is found when M = 0.09. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.09 = 1.96\sqrt{\frac{0.21*0.79}{n}}$