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devlian [24]
4 years ago
13

To the right are the outcomes that are possible when a couple has three children. assume that boys and girls are equally​ likely

, so that the eight simple events are equally likely. find the probability that when a couple has three​ children, there is exactly 1 girl.
Mathematics
1 answer:
hoa [83]4 years ago
7 0

The all possible eight outcomes of boy or girl birth when a couple have three children is

(GBB) , (GBG), (GGB) , (GGG), (BBG), (BGB), (BGG), (BBB)

Where B represents boy and G represents Girl

The probability that having exactly 1 girl is

= Number of outcomes with one girl / Total numbers of outcomes

Now Number of outcomes with only one girl = GBB, BGB, BBG = 3

So the probability will be

The probability that having exactly 1 girl is = 3/8 = 0.375

The probability that when a couple has three​ children, there is exactly 1 girl is 0.375

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Step-by-step explanation:

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3 years ago
The probability that all four test subjects had a true negative test result when they are randomly selected without replacement
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The solution would be like this for this specific problem:

Given:

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Positive Test Result                                                                                         10                           29

(Positive test indicated that the subject lied.)                      (false positive)                  (true positive)

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Formula:

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Therefore, when they are randomly selected without replacement, the <span>probability that all four test subjects had a true negative test result is 0.079</span>.

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The two sales people for a local advertising firm are Trinity and Jason. Trinity sold $2,330 in ads and Jason sold $1,740. What
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The two sales people for a local advertising firm are Trinity and Jason.

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The fractional value of Jason's sales = \frac{1740}{4070}=0.427 or 43%

5 0
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Read 2 more answers
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Hope this helps!
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Answer:

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Step-by-step explanation:

I believe this is the answer

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