First set up a proportion
240/160 = 320/200
Cross multiply and if the left equals the right it is similar.
Answer:y ÷ 2 + x; use x = 1, and y = 2y ÷ 2 + x; use x = 1, and y = 2y ÷ 2 + x; use x = 1, and y = 2y ÷ 2 + x; use x = 1, and y = 2y ÷ 2 + x; use x = 1, and y = 2y ÷ 2 + x; use x = 1, and y = 2y ÷ 2 + x; use x = 1, and y = 2y ÷ 2 + x; use x = 1, and y = 2y ÷ 2 + x; use x = 1, and y = 2y ÷ 2 + x; use x = 1, and y = 2y ÷ 2 + x; use x = 1, and y = 2y ÷ 2 + x; use x = 1, and y = 2
Step-by-step explanation:
A) y = 2x – 7 and f(x) = 7 – 2xIncorrect. These equations look similar but are not the same. The first has a slope of 2 and a y-intercept of −7. The second function has a slope of −2 and a y-intercept of 7. It slopes in the opposite direction. They do not produce the same graph, so they are not the same function. The correct answer is f(x) = 3x2 + 5 and y = 3x2 + 5. B) 3x = y – 2 and f(x) = 3x – 2Incorrect. These equations represent two different functions. If you rewrite the first equation in terms of y, you’ll find the equation of the function is y = 3x + 2. The correct answer is f(x) = 3x2 + 5 and y = 3x2 + 5. C) f(x) = 3x2 + 5 and y = 3x2 + 5Correct. The expressions that follow f(x) = and y = are the same, so these are two different ways to write the same function: f(x) = 3x2 + 5 and y = 3x2 + 5. D) None of the aboveIncorrect. Look at the expressions that follow f(x) = and y =. If the expressions are the same, then the equations represent the same exact function. The correct answer is f(x) = 3x2 + 5 and y = 3x2 + 5.
Answer:
Step-by-step explanation:
The domain of a rational function is all real numbers <em>except </em>for when the denominator equals 0.
So, to find the domain restrictions, set the denominator to 0 and solve for x.
We have the rational function:
Set the denominator to 0:
Subtract 9:
So, the domain is all real numbers except for -9.
In other words, our domain is all values to the left of negative 9 and to the right of negative 9.
In interval notation, this is:
And we're done :)
Answer:
Tn = 2Tn-1 - Tn-2
Step-by-step explanation:
Before we can generate the recursive sequence, we need to find the nth term of the given sequence.
nth term of an AP is given as:
Tn = a+(n-1)d
If a17 = -40
T17 = a+(17-1)d = -40
a+16d = -40 ...(1)
If a28 = -73
T28 = a+(28-1)d = -73
a+27d = -73 ...(2)
Solving both equations simultaneously using elimination method.
Subtracting 1 from 2 we have:
27d - 16d = -73-(-40)
11d = -73+40
11d = -33
d = -3
Substituting d = -3 into 1
a+16(-3) = -40
a - 48 = -40
a = -40+48
a = 8
Given a = 8, d = -3, the nth term of the sequence will be
Tn = 8+(n-1) (-3)
Tn = 8+(-3n+3)
Tn = 8-3n+3
Tn = 11-3n
Given Tn = 11-3n and d = -3
Tn-1 = Tn - d... (3)
Tn-1 = 11-3n +3
Tn-1 = 14-3n
Tn-2 = Tn-2d...(4)
Tn-2 = 11-3n-2(-3)
Tn-2 = 11-3n+6
Tn-2 = 17-3n
From 3, d = Tn - Tn-1
From 4, d = (Tn - Tn-2)/2
Equating both common difference
(Tn - Tn-2)/2 = Tn - Tn-1
Tn - Tn-2 = 2(Tn - Tn-1)
Tn - Tn-2 = 2Tn-2Tn-1
2Tn-Tn = 2Tn-1 - Tn-2
Tn = 2Tn-1 - Tn-2
The recursive formula will be
Tn = 2Tn-1 - Tn-2
