Hello,
1) A odd function has the propriety f(-x)=-f(x)
Answer E
2)
if f(x) is even f(x)=f(-x)
if g(x) is even g(x)=g(-x)
h(x)=f(x)+g(x)=(f+g)(x)
h(-x)=(f+g)(-x)=f(-x)+g(-x)=f(x)+g(x)=(f+g)(x)=h(x)
h(x) is even
Answer:
The inverse will be:
Step-by-step explanation:
In order to find the inverse of the equation, we do a variable change, since we are finding the inverse, :
Now solve for y'.
First add 4 in both sides of the equation and change to the left y'.
= x + 4
Second divide by 9
/9 = (x + 4)/9
= (x + 4)/9
Now you will have to clear y, with the square root.
![[tex]y'^{\frac{2}{2}} = \sqrt{x + 4} / \sqrt{9}](https://tex.z-dn.net/?f=%5Btex%5Dy%27%5E%7B%5Cfrac%7B2%7D%7B2%7D%7D%20%3D%20%5Csqrt%7Bx%20%2B%204%7D%20%20%2F%20%5Csqrt%7B9%7D)
[/tex] =
Simplifying terms
You can check the answer by doing the evaluation of the following equation:
(f o 
) (x)
substitute the equation for y' or inverse function
f(
)
Now substitue the value into f(x)
You will have
=x
Answer:
The equation in point - slope form of a line that passes through the points (3,-5) and (-8,4) is: y-(-5) = -(9/11) (x-3) or y+5 = -(9/11) (x-3)
Step-by-step explanation:
P1=(3,-5)=(x1,y1)→x1=3, y1=-5
P2=(-8,4)=(x2,y2)→x2=-8, y2=4
Equation in Point-Slope Form: y-y1=m(x-x1)
Slope: m=(y2-y1)/(x2-x1)
Replacing the known values:
m=[4-(-5)] / (-8-3)
m=(4+5) / (-11)
m=(9) / (-11)
m=-(9/11)
Equation in the point - slope form:
y-(-5) = -(9/11) (x-3)
y+5 = -(9/11) (x-3)
Answer:
12
Step-by-step explanation:
negative times a negative equals a positive.
so, 6 times 2 is 12.
Answer:
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