Answer:
a. Class width=4
b.
Class midpoints
46.5
50.5
54.5
58.5
62.5
66.5
70.5
c.
Class boundaries
44.5-48.5
48.5-52.5
52.5-56.5
57.5-60.5
60.5-64.5
64.5-68.5
68.5-72.5
Step-by-step explanation:
There are total 7 classes in the given frequency distribution. By arranging the frequency distribution into the refine form we get,
Class
Interval frequency
45-48 1
49-52 3
53-56 5
57-60 11
61-64 7
65-68 7
69-72 1
a)
Class width is calculated by taking difference of consecutive two upper class limits or two lower class limits.
Class width=49-45=4
b)
The midpoints of each class is calculated by taking average of upper class limit and lower class limit for each class.
Class
Interval Midpoints
45-48 
49-52 
53-56 
57-60 
61-64 
65-68 
69-72 
c)
Class boundaries are calculated by subtracting 0.5 from the lower class limit and adding 0.5 to the upper class interval.
Class
Interval Class boundary
45-48 44.5-48.5
49-52 48.5-52.5
53-56 52.5-56.5
57-60 56.5-60.5
61-64 60.5-64.5
65-68 64.5-68.5
69-72 68.5-72.5
Answer:
50/8 , 
, 6.45 , 26/4
Step-by-step explanation:
The numbers are:
26/4 , 6.45 , 6
, 50/8
Converting the numbers to decimal form:
6.5 , 6.45 , 6.4 , 6.25
Arranging from least to greatest:
6.25 , 6.4 , 6.45 , 6.5
Converting back to initial form (in the least to greatest order):
50/8 , 6 , 6.45 , 26/4.
Answer:
In the expression
a in the formula will be substituted for 1
b in the formula will be substituted for -11
c in the formula will be substituted for 10
Answer:
(a) we get that the fewest number of packages of cups and napkins should buy is 24.
(b) Number of sets of 3 packages of Cups and 2 packages of Napkins will be there.
Step-by-step explanation:
Given that,
Cups are sold in packages of 8.
Napkins are sold in package of 12.
To find:- (a) What is the fewest number of packages of cups and the fewest number of packages of napkins that can be purchased so there will be the same number of cups as napkins?
From the Question,
We have to least number of packages of cups and napkins So, we find the
L.C.M of the given data because it provide the least common multiple.
So, L.c.m of 8 & 12 is
Here we get that the fewest number of packages of cups and napkins should buy is 24.
(b) How many sets of cups and napkins will there be?
Again,
Number of packages of cups should buy = 
Number of packages of Napkins should buy = 
Hence
Number of sets of 3 packages of Cups and 2 packages of Napkins will be there.
Scatterplot; correlate ♂️
