Question

The scores of an eighth-grade math test have a normal distribution with a mean Mu = 83 and a standard deviation Sigma = 5. If Din’s test score was 92, which expression would she write to find the z-score of her test score?

Answer 1

The missing choices are:

A. z-score = 92 - 83

B. z-score = (92 - 83)/5

C. z-score = 83 - 92

D. z-score =  (92 - 83)/92

The expression she would write to find z-score is z-score = $\frac{92-83}{5}$ ⇒ B

Step-by-step explanation:

The rule of z-score is z = (x -μ)/σ, where

• x is the score
• μ is the mean
• σ is the standard deviation

The scores of an eighth-grade math test have a normal distribution

∵ The mean is 83

∴ μ = 83

∵ The standard deviation is 5

∴ σ = 5

∵ Din’s test score was 92

∴ x = 92

- Substitute all of these values in the formula of z-score

∴ z-score = $\frac{92-83}{5}$

The expression she would write to find z-score is z-score = $\frac{92-83}{5}$

Learn more:

You can learn more about z-score in brainly.com/question/7207785

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