Describe in words the region of R3 reperesented by the equations or inequalities x2+y2=4,z=-1
1 answer:
Answer:
It represents a circle of radius 2, centered in the origin of the plane xy and transversal to the z-axis in z=-1.
Step-by-step explanation:
The first thing to notice is that
<u>represents a circle of radius 2</u>, with its center in the origin of a plane xy, of cartesians coordinates.
Starting from here, we have to put the coordinate z, to complete the space R³. <em>Then, the cirlce will "live" into the plane xy, where z=-1</em>.
Finally, we have that this region is a circle of radius 2, centered in the origin of the plane xy, and transversal to z=-1.
You might be interested in
Answer:
<h2> 112.3 square units</h2>Step-by-step explanation:
Find the sketch of the triangle attached.
Area of the triangle =
Given PQ = 20, PR = 12 and ∠QPR = 68°
Area of the triangle = 1/2 * 20 * 12 * sin68°
Area of the triangle = 120sin68°
Area of the triangle = 112.26 square units
Area of the triangle ≈ 112.3 square units (to the nearest tenth of a square unit)
Answer:
D
Step-by-step explanation:
you want to solve it out
start with multiplying z to each. you don't multiply it to the 6 because it is in the same parenthesis set, but you multiply it to everything in the other set. After multiplying, you get: ,
,
now do that to the 6. After multiplying you get: ,
,
now set it all next to each other +
+
+
+
+
now combine like terms. start with the to the highest power. since there is only one that has a third power, you put that one first. then you combine the squared ones, and so forth.
work combining the squares:
work combing the single z's:
to get this: +
+
+
so, the answer is D