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Nostrana [21]
2 years ago
9

What are the zeros of the quadratic function f(x)=8^2-16-15

Mathematics
1 answer:
Free_Kalibri [48]2 years ago
6 0

Answer:

C)

Step-by-step explanation:

f(x)=8x^{2} -16x-15
8x^{2} -16x-15=0
x=\frac{-b+-\sqrt{b^{2}-4ac } }{2a}  ,  a=8, b= - 16, c= - 15

x=\frac{-(-16)+-\sqrt{(-16)^2-4*8*(-15)} }{2*8} = \frac{16+-\sqrt{736} }{16} =\frac{16+-4\sqrt{46} }{16} = 1 +- \frac{\sqrt{46} }{4} = 1+- \frac{\sqrt{23} \sqrt{2}}{2\sqrt{2} \sqrt{2} } =1+-\frac{\sqrt{23} }{2\sqrt{2} } = 1+-\frac{\sqrt{23} }{\sqrt{8} }

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The area of a 2D form is the amount of space within its perimeter. The area of the garden is 72 feet² and the perimeter of the garden is 36 feet.

<h3>What is an area?</h3>

The area of a 2D form is the amount of space within its perimeter. It is measured in square units such as cm2, m2, and so on. To find the area of a square formula or another quadrilateral, multiply its length by its width.

The diagram for the given garden is given below.

1.) The area of the garden is,

The area of the garden = Area of rectangle + Area of triangle

                                       = (6 x 8) + (0.5 x 6 x 8)

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2.) The perimeter of the garden is,

The perimeter of the triangle = 12 + 8 + 6 + 10 = 36 feet

Hence, the area of the garden is 72 feet² and the perimeter of the garden is 36 feet.

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<u>Given:</u>

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