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3 years ago

What equation shows the relationship between the profit function, cost function and revenue function?

Mathematics

1 answer:

vlabodo [156]3 years ago

6 0

Profit function - Cost function = Revenue function

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G(x)=3x^2+6x−9<br><br> I need the vertex for this please

aleksley [76]

Answer:

-1, -12

Step-by-step explanation:

you take b which is 6 and make it negative, then you take a and multiply it by 2, which is 6. you then take the 2 numbers and put the -b over 2a in this formula -b/2a giving you -1 as your x value

after you do that, you input the -1 into the equation as x and the value you get out of that (-12) is the y value of the vertex

5 0

3 years ago

Kori spent 46.20 on 12 gallons of gasoline.what was the price per gallon?

Sav [38]

$3.85 per gallon is the price per gallon

3 0

4 years ago

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The absolute values of two numbers that are additive inverses will ____________ be the same.

zhannawk [14.2K]

Answer:

A number and its additive inverse are always the same distance from zero, and so they have the same absolute value.

Step-by-step explanation:

Hope this helps!!

7 0

3 years ago

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Triangle ABC has vertices at A(-2,1), B(-2,-3), and C(1,-2). What is the area of the triangle? a 18 square units b 9 square unit

natka813 [3]

Answer:

Option C. 6 square units

Step-by-step explanation:

we know that

Heron's Formula is a method for calculating the area of a triangle when you know the lengths of all three sides.

Let

a,b,c be the lengths of the sides of a triangle.

The area is given by:

$A=\sqrt{p(p-a)(p-b)(p-c)}$

where

p is half the perimeter

p= $\frac{a+b+c}{2}$

we have

Triangle ABC has vertices at A(-2,1), B(-2,-3), and C(1,-2)

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

$d=\sqrt{(-3-1)^{2}+(-2+2)^{2}}$

$d=\sqrt{(-4)^{2}+(0)^{2}}$

$dAB=4\ units$

step 2

Find the distance BC

$d=\sqrt{(-2+3)^{2}+(1+2)^{2}}$

$d=\sqrt{(1)^{2}+(3)^{2}}$

$dBC=\sqrt{10}\ units$

step 3

Find the distance AC

$d=\sqrt{(-2-1)^{2}+(1+2)^{2}}$

$d=\sqrt{(-3)^{2}+(3)^{2}}$

$dBC=\sqrt{18}\ units$

step 4

$a=AB=4\ units$

$b=BC=\sqrt{10}\ units$

$c=AC=\sqrt{18}\ units$

Find the half perimeter p

p= $\frac{4+\sqrt{10}+\sqrt{18}}{2}=5.70\ units$

Find the area

$A=\sqrt{5.7(5.7-4)(5.7-3.16)(5.7-4.24)}$

$A=\sqrt{5.7(1.7)(2.54)(1.46)}$

$A=\sqrt{35.93}$

$A=6\ units^{2}$

7 0

3 years ago

4) Find the sum of 6\12 and 1\2 .A) 3\12 B) 9\12 C) 12\12 D) 13\12

Darina [25.2K]

Answer:

12/12

Step-by-step explanation:

6/12= 1/2

so 1/2+1/2 = One Whole and that the same thing as 12/12

5 0

3 years ago

Read 2 more answers