Answer:
By these examples you are able to see that the square of an odd number is always 1 more than a multiple of 4.
Step-by-step explanation:
For examples,
Let's consider squares of 3, 11, 25, 37 and 131.
8 is a multiple of 4, and 9 is more than 8.
120 is a multiple of 4 and 121 is one more than it.
624 is a multiple of 4 and 625 is one more than it.
1368 is a multiple of 4 and 1369 is one more than 1368.
17160 is a multiple of 4.
Answer:x=65 y=155 ur welcome
For questions #6 & #8, you didn't complete them or provide all necessary things (such as description, data, or graph). 5 − ≤ 20 is not an inequality, an inequality should be something like 5 - x ≤ 20, but you didn't give anything like that in your question.
7. (-1,4), (5,2), we can calculate the slope. As x increases from -1 to 5, (increases by 6), the y-value decreases by 2. -2/6 = -1/3, the slope is -1/3. The slope is negative and the y-value decreases by a third of the amount the x-value changes.
9. C, because you can only hold at MOST 500, and larger watermelons is represented by 10x. I'm assuming you made an error in your question, you gave me the values of larger/smaller watermelons only, and your question asked for larger & medium and the options seem to suggest there's only larger/smaller. 10x + 3y <= 500 or <, smaller than or equal would be the better choice if available.
10. y = 2x + 10, because 2 is the slope as minutes increase by 1, inches increase by 2, and the 10 inches of sawdust are already there.
When you offer Questions #6 & #8's data, I'll gladly help you with it. The rest of the questions are correct and properly explained.
1/2 x s, where s equals 3/10 means,
(1/2) x (3/10) which will give (3/20)
You simply multiply the numerators to get 3 and the denominators to get 20.
Answer: See the answers below.
The first equation that needs to be solve is: 10 = -16t^2 + 18
If you use the quadratic equation, you will get 0.707 seconds.
For the second equation, you need to solve 0 = -16t^2 + 18.
If you use the quadratic equation, you will get 1.061 seconds.
No, the rate of change is not constant because this is a quadratic equation.
