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Juli2301 [7.4K]
3 years ago
9

a man drives x miles the first day, y miles the second day, and z miles the third day. the averge mileage covered per day is

Mathematics
1 answer:
statuscvo [17]3 years ago
6 0
The average mileage covered per day is = number of miles / number of days.

The average mileage covered per day is =(x+y+z)/3
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Is 1.75 a reasonable estimate of the value of the square root of 8
ladessa [460]

Answer:

Test it.  Is 1.752 close to 8?

1.752 = 3.0625

3.0625 is not close to 8.

Step-by-step explanation:

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2 years ago
A student used the point-slope form to write the equation of a line that has a slope of Three-fourths and passes through the poi
UNO [17]

Answer:y=3/4x-17/4

Step-by-step explanation:

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2 years ago
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Maggie's brother is 6 years younger than four times her age. The sum of their ages is 39. How old is Maggie?
poizon [28]

We can set Maggie's age to x

If her brother is six years younger than four times her age, than her brother must be equal to: 4x-6

Since the sum of their ages is 39, we can set up an equation.

(Sum of Maggie's age) + (sum of Maggie's brother's age) = 39

x + (4x -6) = 39

5x -6 = 39

5x = 45

x = 9 , Maggie's age is 9

6 0
2 years ago
We know that logarithmic functions are a bit more unusual than functions we’ve seen in the past, such as linear, exponential, qu
AnnyKZ [126]

Answer:

Step-by-step explanation:

can you re-phrase that please then i can answer

7 0
2 years ago
40, 10, 5/2 5/8... (fractions) is it arithmetic or geometric and what are the next two terms PLZ HELP DUE IN 10 MINS
patriot [66]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the sequence

40,\:10,\:\frac{5}{2},\:\frac{5}{8}

A geometric sequence has a constant ratio 'r' and is defined by

\:a_n=a_0\cdot r^{n-1}

Computing the ratios of all the adjacent terms

\frac{10}{40}=\frac{1}{4},\:\quad \frac{\frac{5}{2}}{10}=\frac{1}{4},\:\quad \frac{\frac{5}{8}}{\frac{5}{2}}=\frac{1}{4}

The ratio of all the adjacent terms is the same and equal to

r=\frac{1}{4}

Thus, the given sequence is a geometric sequence.

As the first element of the sequence is

a_1=40

Therefore, the nth term is calculated as

\:a_n=a_0\cdot r^{n-1}

a_n=40\left(\frac{1}{4}\right)^{n-1}

Put n = 5 to find the next term

a_5=40\left(\frac{1}{4}\right)^{5-1}

a_5=40\cdot \frac{1}{4^4}

a_5=\frac{40}{4^4}

   =\frac{2^3\cdot \:5}{2^8}

a_5=\frac{5}{2^5}

a_5=\frac{5}{32}

now, Put n = 6 to find the 6th term

a_6=40\left(\frac{1}{4}\right)^{6-1}

a_6=40\cdot \frac{1}{4^5}

a_6=\frac{40}{4^5}

    =\frac{2^3\cdot \:5}{2^{10}}

a_6=\frac{5}{2^7}

a_6=\frac{5}{128}

Thus, the next two terms of the sequence 40, 10, 5/2, 5/8... is:

  • a_5=\frac{5}{32}
  • a_6=\frac{5}{128}
7 0
3 years ago
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