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1 answer:
Answer:
y = - 6x - 2
Step-by-step explanation:
The straight line equation is y = mx + c
First step is to bring the equation given to this form, where you make y the subject.
Now you can easily note down the gradient(m1). You will need it to find the gradient(m2) of the perpendicular line, because m1 × m2 = -1
After you have that substitute the value and the values of x and y given to find c .
Lastly, substitute the value of m2 and c into y = mx + c to find the line that is perpendicular .
Hope I was able to help:)))
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Check the attachment(s) for the graphs pertaining to the question
No. 1) Check graph [first attachment]
No. 2) y = (x - 2)^2 - 3, y = 1
(x - 2)^2 - 3 = 1,
(x - 2)^2 = 4
x - 2 = √4, x - 2 = - √4
x = 4, x = 0
Substitute back to determine the respectively y-value:
y = (4 - 2)^2 - 3 = (2)^2 - 3 = 4 - 3 = 1
Check: y = (0 - 2)^2 - 3 = (-2)^2 - 3 = 4 - 3 = 1
So the points of intersection are (4, 1) and (0, 1). According to the graph, that is correct.
Answer: The side of the square will be 3 cm.
Step-by-step explanation:
When squares of equal size of side x, are cut from the four corners, we are left with the following dimensions for the cuboid box.
l= 30-2x
b = 14-2x
h= x
Hence, the volume of the cuboid will be ,
V = lbh
= (30-2x)(14-2x)x
Since this volume should be the largest possible, then differentiating volume with x should be equal to zero.
Therefore,
solving we get, x = 3, x =
We can omit x = because 14 - 2x < 0 , which is not possible.
Therefore, x=3.
