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Nana76 [90]
3 years ago
16

Yoko is trying to save money for a new bicycle. She sets up a budget as shown below. Yoko’s Monthly Budget Description Income Po

sitive Expenses Negative Earnings (babysitting) $125 Earnings (bagging groceries) $55 Entertainment $25 Snacks $10 Transportation $25 Clothing $35 Amount available for savings: $ How much money will Yoko have left over for her savings each month? $85 $95 $110 $120
Mathematics
2 answers:
KonstantinChe [14]3 years ago
5 0

Answer:

$85

Step-by-step explanation:

<u>Earning:</u>

  • $125 + $55 = $180

<u>Spending:</u>

  • $25 + $10 + $25 + $35 = $95

<u>Amount available for saving:</u>

  • $180 - $95 = $85
Tema [17]3 years ago
4 0

Answer: $85

Step-by-step explanation: Took the test and got it correct

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What are the all solutions to the following equation? |3x+2|=17
Rom4ik [11]

Answer:

I don't know. truncating your text book

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2 years ago
You are playing a game in which a single die is rolled. If a 2 or 5 comes up you win $36. Otherwise, you lose $36. What is your
algol13
1/3 wins and 2/3 losses
given 2 and 5 = 2/6 = 1/3
1, 3, 4, and 6 = 4/6 = 2/3
7 0
3 years ago
Find all solutions of the equation in the interval [0, 2 pi) 2 cos0-1=0
ddd [48]

Answer:

θ = π/3, 5π/3

Step-by-step explanation:

2 cos θ - 1 = 0

2 cos θ = 1

cos θ = 1/2

θ = π/3, 5π/3

7 0
3 years ago
Read 2 more answers
What are the possible rational roots of the polynomial equation?<br><br> 0=2x7+3x5−9x2+6
RoseWind [281]

Answer: \pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}

Step-by-step explanation:

We can use the Rational Root Test.

Given a polynomial in the form:

a_nx^n +a_{n- 1}x^{n - 1} + … + a_1x^1 + a_0 = 0

Where:

- The coefficients are integers.

- a_n is the leading coeffcient (a_n\neq 0)

- a_0 is the constant term a_0\neq 0

Every rational root of the polynomial is in the form:

\frac{p}{q}=\frac{\pm(factors\ of\ a_0)}{\pm(factors\ of\ a_n)}

For the case of the given polynomial:

2x^7+3x^5-9x^2+6=0

We can observe that:

- Its constant term is 6, with factors 1, 2 and 3.

- Its leading coefficient is 2, with factors 1 and 2.

 Then, by Rational Roots Test we get the possible rational roots of this polynomial:

\frac{p}{q}=\frac{\pm(1,2,3,6)}{\pm(1,2)}=\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}

5 0
2 years ago
The perimeter of a particular square and the circumference of a particular circle are equal. What is the ratio of the area of th
oksano4ka [1.4K]
<h2>Ratio of area of the square to the area of the circle = π/4</h2>

Step-by-step explanation:

Let the side of square be a and radius of circle be r.

The perimeter of a particular square and the circumference of a particular circle are equal.

Perimeter of square = 4 x a = 4a

Circumference of circle = 2πr

Given that

                      4a = 2πr

                        a=\frac{\pi r}{2}

We need to find the ratio of the area of the square to the area of the circle.

Area of the square = a²

Area of the circle = πr²

\texttt{Ratio of area of the square to the area of the circle =}\frac{a^2}{\pi r^2}\\\\\texttt{Ratio of area of the square to the area of the circle =}\frac{\left ( \frac{\pi r}{2}\right )^2}{\pi r^2}\\\\\texttt{Ratio of area of the square to the area of the circle = }\frac{\pi}{4}

Ratio of area of the square to the area of the circle = π/4

6 0
2 years ago
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