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Step2247 [10]
3 years ago
14

What is the slope of the line that runs through points (-7,-20) and (12,18)?  Write the equation of that line.

Mathematics
2 answers:
Ilia_Sergeevich [38]3 years ago
7 0

Answer:

The slope is 2 which means the equation would be y=2x.

Step-by-step explanation:

gavmur [86]3 years ago
3 0

Answer:

2

Step-by-step explanation:

-20 - 18 = -38

-7 - 12 = -19

-38/-19 = 2

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Using the segment addition postulate, which is true? A number line going from negative 9 to positive 9. A closed circle appears
MArishka [77]

Answer:

  BC + CD = BD

Step-by-step explanation:

The segment addition postulate tells you that when a segment is divided into two parts, the sum of the lengths of the first part of the divided segment and the second part of the divided segment will be equal to the length of the whole segment.

If point C divides segment BD into BC and CD, then the sum of those two segments will match the whole.

4 0
3 years ago
Read 2 more answers
Sarah is purchasing pencils to share. Each package has 12 pencils. The equation n = 12p, where n is the total number of pencils
podryga [215]

Answer and Step-by-step explanation:

Each package has 12 pencils

total number of pencils Sarah purchased: n = 12p

n = total number of pencils

p = number of packages

n depends on p, because the total number of pencils dependos on how many packages she will buy, so:

independent variable: p

dependent variable: n

╔═══╦══════════╦════╗

║ p     ║ n = 12p            ║ n  ║

╠═══╬══════════╬════╣

║ 3     ║ n = 12*3           ║ 36     ║

╠═══╬══════════╬════╣

║ 4     ║ n = 12*4           ║ 48     ║

╠═══╬══════════╬════╣

║ 5     ║ n = 12*5           ║ 60     ║

╠═══╬══════════╬════╣

║ 6     ║ n = 12*6           ║ 72     ║

╠═══╬══════════╬════╣

║ 7     ║ n = 12*7           ║ 84     ║

╚═══╩══════════╩════╝

7 0
3 years ago
Jeremy bought a 5-kilogram can of peanuts for $4.50. What is the unit price?
Goryan [66]

Answer:

$0.90

Step-by-step explanation:

you would divide it by 5

$4.50/5=$0.90

hope this helps

brainliest?

6 0
3 years ago
Given:
V125BC [204]

Answer:

10 since its half of the original

6 0
2 years ago
Find the solution of the differential equation that satisfies the given initial condition. y' tan x = 3a + y, y(π/3) = 3a, 0 &lt
Paladinen [302]

Answer:

y(x)=4a\sqrt{3}* sin(x)-3a

Step-by-step explanation:

We have a separable equation, first let's rewrite the equation as:

\frac{dy(x)}{dx} =\frac{3a+y}{tan(x)}

But:

\frac{1}{tan(x)} =cot(x)

So:

\frac{dy(x)}{dx} =cot(x)*(3a+y)

Multiplying both sides by dx and dividing both sides by 3a+y:

\frac{dy}{3a+y} =cot(x)dx

Integrating both sides:

\int\ \frac{dy}{3a+y} =\int\cot(x) \, dx

Evaluating the integrals:

log(3a+y)=log(sin(x))+C_1

Where C1 is an arbitrary constant.

Solving for y:

y(x)=-3a+e^{C_1} sin(x)

e^{C_1} =constant

So:

y(x)=C_1*sin(x)-3a

Finally, let's evaluate the initial condition in order to find C1:

y(\frac{\pi}{3} )=3a=C_1*sin(\frac{\pi}{3})-3a\\ 3a=C_1*\frac{\sqrt{3} }{2} -3a

Solving for C1:

C_1=4a\sqrt{3}

Therefore:

y(x)=4a\sqrt{3}* sin(x)-3a

3 0
3 years ago
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