The total cost that will be paid by the family will be RM(15x - y).
<h3>How to calculate the cost?</h3>
The entrance fee to a circus for a child is RM(3x-y).
The entrance fee for an adult is RM(3x - y) + RM2y = 3x + y.
Therefore, the cost for 2 adults and three children will be:
= 2(3x + y) + 3(3x - y)
= 6x + 2y + 9x- 3y
= 15x - y
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15×1.06
=15.9
therefor it is $15.90
This expression is already simplified.
Answer:
just by looking at the graph you can see that the y int is one, so that eliminates two answers already. Then the slope is rise over run. (best thing to remember in math. rise over run) so pick two points. (0, 1) and (4,0) were the first ones i saw. to get from those two points you go from (0,1) over 4 (thats your run) and from there down 1 (thats your rise) to get to (0,4). You would then do rise over run (and because your rise goes down its negative) to get -1/4 as your slope. The answer is slope= -1/4, Y intercept = 1
A. True. We see this by taking the highest order term in each factor:
![f(x) = -3x(x-5)^3(x+2)^2 = -3x (x^3 + \cdots) (x^2 + \cdots) = -3x^{\boxed{6}} + \cdots](https://tex.z-dn.net/?f=f%28x%29%20%3D%20-3x%28x-5%29%5E3%28x%2B2%29%5E2%20%3D%20-3x%20%28x%5E3%20%2B%20%5Ccdots%29%20%28x%5E2%20%2B%20%5Ccdots%29%20%3D%20-3x%5E%7B%5Cboxed%7B6%7D%7D%20%2B%20%5Ccdots)
B. True. Again we look at the leading term's degree and coefficient. f(x) behaves like -3x⁶ when x gets large. The degree is even, so as x goes to either ± ∞, x⁶ will make it positive, but multiplying by -3 will make it negative. So on both sides f(x) approaches -∞.
C. False. f(x) = 0 only for x=0, x = 5, and x = -2.
D. False. Part of this we know from the end behavior discussed in part B. On any closed interval, every polynomial is bounded, so that for any x in [-2, 5], f(x) cannot attain every positive real number.
E. True. x = 0 is a root, so f(0) = 0 and the graph of f(x) passes through (0, 0).
F. False. (0, 2) corresponds to x = 0 and f(x) = 2. But f(0) = 0 ≠ 2.