12
change the mixed numbers to improper fractions before dividing
1
=
and 15
= 
divide contents of box by a serving
÷ 
change ÷ to × and turn the second fraction upside down
=
× 
=
= 12.26666 = 12 complete servings
Answer:
Step-by-step explanation:
Recall that the ratio test is stated as follows:
Given a series of the form 
If L<1, then the series converge absolutely, if L>1, then the series diverge. If L fails to exist or L=1, then the test is inconclusive.
Consider the given series
. In this case,
, so , consider the limit

Since the numerator has a greater exponent than the numerator, the limit is infinity, which is greater than one, hence, the series diverge by the ratio test
Write the equation of the line through (5,-4); m = 1
11/12
simplificado
de nada