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PtichkaEL [24]
3 years ago
15

What is the rule for the reflection?

Mathematics
1 answer:
Sliva [168]3 years ago
7 0
Hey user!

your answer is here...

laws ( rules ) of reflection are :-

• angle of incidence is equal to angle of reflection.

• the incident ray, Normal ray and reflected ray all lie in same plane.

cheers!!

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The net change for a certain stock is the dollar value change in the
Kaylis [27]

Answer:

-3

Step-by-step explanation:

Just put that trust me

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3 years ago
FREE POINT ANSWER QUESTION AND GET A BOX OF CEARAL!!!
ddd [48]

Answer:

cubes are 3-d while squares are 2-d so in order to solve them you need different equations.

7 0
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Read 2 more answers
The coach recorded how fast his runners ran 1 mile. Emmett ran a mile in 9.73 minutes Kate ran a mile in 10.87 minutes how many
igor_vitrenko [27]

Complete Question

The coach recorded how fast his runners ran 1 mile. Emmett ran a mile in 9.73 minutes, Kate ran a mile in 10.87 minutes, and Rubin ran a mile in 8.46 minutes. How many more minutes did Emmett run than Robin?

a. 1.37 minutes

b. 1.27 minutes

c. 2.27 minutes

d. 1.27 seconds

Answer:

1.27 minutes

Step-by-step explanation:

Emmett ran a mile in 9.73 minutes

Kate ran a mile in 10.87 minutes

Rubin ran a mile in 8.46 minutes.

How many more minutes did Emmett run than Robin?

This is calculated as:

Number of minutes Emmett ran - Number of minutes Rubin ran

= 9.73 minute - 8.46 minutes

= 1.27 minutes

Option b is correct

5 0
2 years ago
If a phone card is used to make a long distance phone call, you are charged $0.50 per call plus an additional $0.31 per minute.
Nikitich [7]

Part A: c for cost. c=0.31m+0.5

0.31m is the cost per minute. 0.5 is cost per call.

Part B: 0.31m+0.5=5.15 to solve we must rearrange.

subtract 0.5 from each side giving us 0.31m=4.85

divide by 0.31 giving us m=15.65

7 0
3 years ago
How many solutions does the equation |x + 6| − 4 = c have if c = 5? If c = −10? Complete the explanation
mixer [17]

Answer:

<h2>For c = 5 → two solutions</h2><h2>For c = -10 → no solutions</h2>

Step-by-step explanation:

We know

|a|\geq0

for any real value of <em>a</em>.

|a| = b > 0 -  <em>two solutions: </em>a = b or a = -b

|a| = 0 - <em>one solution: a = 0</em>

|a| = b < 0 - <em>no solution</em>

<em />

|x + 6| - 4 = c

for c = 5:

|x + 6| - 4 = 5           <em>add 4 to both sides</em>

|x + 6| = 9 > 0   <em>TWO SOLUTIONS</em>

for c = -10

|x + 6| - 4 = -10           <em>add 4 to both sides</em>

|x + 6| = -6 < 0   <em>NO SOLUTIONS</em>

<em></em>

Calculate the solutions for c = 5:

|x + 6| = 9 ⇔ x + 6 = 9 or x + 6 = -9         <em>subtract 6 from both sides</em>

x = 3 or x = -15

5 0
2 years ago
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