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2 years ago

Simplify 3^1/2 * 3^1/2. Show work

1 answer:

Nadusha1986 [10]2 years ago

3 0

First do 3x3, which is 6.
Then do 1/2 x 1/2. Convert the 1/2's to .50's
Do .50 x .50. Start with 5 x 5, and get 25. Then move decimal 2 places over.
Now that you have 6 and .25, add them and get 6.25.
.25 as a fraction is, of course, 1/4
Your final answer should be 6 1/4

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Which numbers are 9 units from −5 on this number line?

ExtremeBDS [4]

Using the number line, the numbers that are 9 units from -5 are: -14 and 4.

<h3>How to Locate a Number on a Number line?</h3>

To find two numbers that cover the same units from a given point on a number line, we can simply do the following:

Count the number of units given backwards/to the left from the point stated to get the first number.
Count the number of units given forwards/to the right from the point stated to get the second number.

Thus, we are asked to find the numbers that would be 9 units from -5, using the number line.

Count 9 units backwards/to the left from -5 to get the first number, which is: -14

Count 9 units forwards/to the right from the -5 to get the second number, which is: 4.

Therefore, the numbers that are 9 units from -5 on the number line, are: -14 and 4.

Learn more about number line on:

brainly.com/question/24644930

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8 0

1 year ago

If D is midpoint of side BC of triangle ABC. P and Q are points lying respectively on side AB and AC such that DP is parallel to

LUCKY_DIMON [66]

See proof below

Step-by-step explanation:

Assume triangle ABC to have vertices at;

A(2,-1), B(2,-7) and C(6,-7)

D is midpoint of BC, thus D is at (4,-7)

The P and Q, are lying on side AB and AC, hence assume P is at (2,-4) and Q is at (4,-4) such at DP is parallel to QA

Plot the points on a graph tool and join the points to view the sketch.

To prove area of triangle CPQ is 1/4 area of ABC will be;

Find area ABC and CPQ then compare the areas.

Apply the distance formula to find the length of sides of the triangles then find the areas.

The distance formula is;

$d=\sqrt{x_2-x_1)^2+(y_2-y_1)^2}$

Length of side AB from the sketch is;

$AB=\sqrt{(2-2)^2+(-7--1)^2} =\sqrt{-6^2} =\sqrt{36} =6units$

Length of side BC will be;

$BC=\sqrt{(-7--7)^2+(6-2)^2} =\sqrt{4^2} =\sqrt{16} =4units$

Thus area of triangle ABC will be;

1/2 *base length*height ------because it is a right-triangle

1/2*4*6=12 square units

Find the lengths of all sides of triangle CPQ

Length of side PQ is half that of side BC thus PQ=2 units

Length of side PC is;

$PC=\sqrt{(6-2)^2+(-7--4)^2} =\sqrt{4^2+-3^2} =\sqrt{16+9} =\sqrt{25} =5units$

Length of side QC will be;

$QC=\sqrt{(6-4)^2+(-7--4)^2} =\sqrt{2^2+-3^3} =\sqrt{4+9} =\sqrt{13}$

QC= √13 = 3.6 units

Find area of triangle CPQ given all sides by applying the Heron's formula for area of triangle which is;

A=√s(s-a)(s-b)(s-c) where;

A=area of the triangle

s= half the perimeter of the triangle

a=side PQ = 2 units

b=side PC = 5 units

c= side QC = 3.6 units

Finding the perimeter of triangle CPQ will be;

P=sum of all sides

P=2+5+3.6 =10.6 units

s=10.6/2 = 5.3

Area of the triangle CPQ will be;

$A=\sqrt{5.3(5.3-2)(5.3-5)(5.3-3.6)} \\A=\sqrt{5.3(3.3)(0.3)(1.7)} \\A=\sqrt{8.9} =2.98$

A=3.0 (1 decimal place)

Compare the areas;

Area of triangle ABC=12 square units

Area of triangle CPQ = 3 square units

Area of triangle CPQ / Area of triangle ABC = 3/12 =1/4

Thus you have proved that area of triangle CPQ is 1/4 th area of triangle ABC because 1/4 *12 =3

Learn More

Area of a triangle ;brainly.com/question/14869984

The Heron's formula : brainly.com/question/10713495

Keywords: midpoint, triangle, sides, parallel, prove , area, equal

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3 years ago

What are the dimensions (length and width) if the poster is enlarged by a factor of 1.5 ? (Remember multiply the factor by the d

Veseljchak [2.6K]

Use socratic or photomath

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3 years ago

When writing a proof, how do you construct the first statement?

Vlad [161]

Answer:c

Step-by-step explanation:

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3 years ago

Read 2 more answers

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irinina [24]

The answer is B, there’s no solution.

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2 years ago