Answer:
32√5
Step-by-step explanation:
We have the right triangles PQA and PQB as well as the given right triangle QAB.
cot(PAQ) = 2/5 = QA/PQ
cot(PBQ) = 3/5 = QB/PQ
cot(PAQ) / cot(PBQ) = (2/5) / (3/5) = 2/3
cot(PAQ) / cot(PBQ) = (QA/PQ) / (QB/PQ) = QA / QB
QA / QB = 2/3
QA = (2/3) QB
QB = (3/2) QA
By the Pythagorean Theorem we have:
(QA)² + 32² = (QB)²
(QA)² + 32² = (3/2 QA)²
(QA)² + 1024 = (9/4) (QA)²
(5/4) (QA)² = 1024
(QA)² = (4/5)1024 = 4096/5
QA = 64/√5
Solve for PQ.
cot(PAQ) = QA/PQ
PQ = QA / cot(PAQ)
PQ = (64/√5) / (2/5) = 32√5
The height of the tower is 32√5.
Answer:

Step-by-step explanation:
we know that
To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.
we will proceed to verify each case to determine the solution of the problem
<u>case A)</u> 
Find the inverse of f(x)
Let
y=f(x)
Exchange variables x for y and y for x
Isolate the variable y


Let


therefore
f(x) and g(x) are inverse functions
<u>case B)</u> 
Find the inverse of f(x)
Let
y=f(x)
Exchange variables x for y and y for x
Isolate the variable y


Let


therefore
f(x) and g(x) are inverse functions
<u>case C)</u> ![f(x)=x^{5}, g(x)=\sqrt[5]{x}](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B5%7D%2C%20g%28x%29%3D%5Csqrt%5B5%5D%7Bx%7D)
Find the inverse of f(x)
Let
y=f(x)
Exchange variables x for y and y for x
Isolate the variable y
fifth root both members
![y=\sqrt[5]{x}](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B5%5D%7Bx%7D)
Let

![f^{-1}(x)=\sqrt[5]{x}](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%3D%5Csqrt%5B5%5D%7Bx%7D)
therefore
f(x) and g(x) are inverse functions
<u>case D)</u> 
Find the inverse of f(x)
Let
y=f(x)
Exchange variables x for y and y for x
Isolate the variable y





Let



therefore
f(x) and g(x) is not a pair of inverse functions
In a equation you would look at the slope which would be multiplied by x
In a graph you would do rise over run
For a table you would do burpees which would give you slope or rate of change
Least- 2
Greatest- 12
Median- 7
Lower Q- 4
Upper Q- 8
Range-10
IQR- 4
Amount from dimes would be: 0.1y
Amount from quarters = 0.25x
So, total amount = 0.25x + 0.1y
So, she is not correct
Hope this helps!