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LiRa [457]
3 years ago
14

The sum of Pete's and Sam's ages is 30. Five years ago, Pete was 3 times as old as Sam. How old is Sam?

Mathematics
2 answers:
abruzzese [7]3 years ago
5 0

Answer : The equation complete the system is, P-5=3S-15 and the Sam is 10 years old.

Step-by-step explanation :

As we are given that sum of Pete's and Sam's ages is 30. Thus, the equation will be:

P+S=30     ..............(1)

P=30-S        ..............(A)

And, five years ago, Pete was 3 times as old as Sam. Thus, the equation will be:

(P-5)=3\times (S-5)     ..............(2)

P-5=3S-15

Now substituting equation A in equation 2, we get:

(P-5)=3\times (S-5)

(30-S-5)=3\times (S-5)

30-S-5=3S-15

30+15-5=3S+S

40=4S

S=\frac{40}{4}

S=10

Now put the value of 'S' in equation A, we get the value of 'P'.

P=30-S

P=30-10

P=20

The age of Pete is, 20 and the age of Sam is, 10

Thus, the equation complete the system is, P-5=3S-15 and the Sam is 10 years old.

RUDIKE [14]3 years ago
4 0
P-5=3s-15 because Pete is 20 and Sam is 10. 20-5= 15 and 3(10)-15 also equals 15. The answer is C.
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-8(8 - x) = 4/5(x + 10)
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Answer:

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Step-by-step explanation:

Solve for x:

-8 (8 - x) = (4 (x + 10))/5

Multiply both sides by 5:

-8×5 (8 - x) = (5×4 (x + 10))/5

(5×4 (x + 10))/5 = 5/5×4 (x + 10) = 4 (x + 10):

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5 (-8) = -40:

-40 (8 - x) = 4 (x + 10)

Expand out terms of the left hand side:

40 x - 320 = 4 (x + 10)

Expand out terms of the right hand side:

40 x - 320 = 4 x + 40

Subtract 4 x from both sides:

(40 x - 4 x) - 320 = (4 x - 4 x) + 40

40 x - 4 x = 36 x:

36 x - 320 = (4 x - 4 x) + 40

4 x - 4 x = 0:

36 x - 320 = 40

Add 320 to both sides:

36 x + (320 - 320) = 320 + 40

320 - 320 = 0:

36 x = 40 + 320

40 + 320 = 360:

36 x = 360

Divide both sides of 36 x = 360 by 36:

(36 x)/36 = 360/36

36/36 = 1:

x = 360/36

The gcd of 360 and 36 is 36, so 360/36 = (36×10)/(36×1) = 36/36×10 = 10:

Answer:  x = 10

7 0
3 years ago
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