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ziro4ka [17]
2 years ago
12

Kendra’s xylophone is in the shape of the trapezoid shaken at the right. Describe any parallel,perpendicular, or congruent sides

of the xylophone.
I NEED HELP

Mathematics
1 answer:
Nookie1986 [14]2 years ago
6 0
The left and right sides make up the parallel sides of the trapezoid.  The top and bottom would be congruent but not parallel.
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3. The 7th grade students took a survey about which pizza company the students
elena-14-01-66 [18.8K]

Answer:

40 students choose Papa John's, and 24 did not

Step-by-step explanation:

This question can be solved by proportions, using rule of three.

For each 8 students, 5 chose Papa John's. Out of 64, how many choose?

5 - 8

x - 64

Applying cross multiplication

8x = 5*64

Simplifying by 8

x = 5*8 = 40

40 students choose Papa John's.

In all, there are 64 students, so 64 - 40 = 24 did not

5 0
2 years ago
Solve the equations by substitution method: A) x+y=3, 2x+5y=12.​
Wittaler [7]

Answer:

x = 1, y = 2

Step-by-step explanation:

Original equations:

x+y=3\\2x+5y=12

Substitute y and solve for x:

y=3-x\\2x+5y=12

2x+5(3-x)=12

2x+15-5x=12

-3x=-3

x=1

Plug in x to solve for y:

1+y=3

y=2

x = 1, y = 2

Note: You can also substitute x and solve for y, then plug in y to solve for x. I did not do that here.

4 0
3 years ago
Read 2 more answers
The function f(h)=m(1/2)^h gives the mass, m, of a radioactive substance remaining after h half-lives. Cobalt-60 has a half-life
goldfiish [28.3K]

Answer:

Third choice:

                f(x)=50(0.877)^{10};13.5mg

Explanation:

<u />

<u>1. Data:</u>

<u />

  • Function:

                f(h)=m(1/2)^h

  • Cobalt-60's half-life: 5.3 years

  • Initial mass of cobalt-60:  50 mg

<u>2. Unknown: </u>

<u />

  • equation for the mass of cobalt-60 remaining after 10 years = ?

  • mass remaining =?

<u>3. Solution</u>

<em>Half-life</em> is the time it takes a sample to  decay to half of its initial amount. It is considered constant. Hence, when one half-life passes, the sample has decayed to 50% of the original amount; when two half-lives pass, the sample has decayed to (1/2)×(1/2) = 1/4 = 25%; when three half-lives have elapsed, the sample has decayed to (1/2)³ = 1/8 = 12.5% of its original amount, and so on.

Then, the amound of a sample remaining is calculated as the original amount times (1/2) raised to the number of half-lives elapsed, which is what the given function,  f(h)=m(1/2)^h models.

You just must substitute the data into the function to get the answer to the question:

            f(x)=50(0.5)^{(10/5.3)}

Where, 50 is the original mass of 50g, 0.5 is equal to 1/2, and 10/5.3 gives the number of half-lives (the number of times that 5.3 years is contained in 10 years).

<u>Simplifying:</u>

f(x)=50(0.5)^{(10/5.3)}=50((0.5)^{(1/5.3})^{10}\approx50(0.877)^{10}

Which corresponds to the third choice of the list.

<u>Computing:</u>

               f(x)\approx50(0.877)^{10}=13.5

Which also corresponds to the third choice.

4 0
3 years ago
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tino4ka555 [31]

Answer:

Step-by-step explanation

cross-section is 10 inches by 16 inches

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Brainlest!
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Answer:

A

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The parabola ends at 4, and therefore the range is all real numbers under 4

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