Question

Jana hit a golf ball with an initial velocity of 102 ft per second at an angle of 67 degrees with the horizontal. After 2 second how far had the ball traveled horizontally? after 3 seconds how far has the ball traveled vertically?

Answer 1

Horizontal distance x(t) = ut cos θ
x(2) = 102 * 2 * cos 67 = 79.7 ft.

Vertical distance y(t) = ut sin θ - 1/2 gt^2
y(3) = 102 * 2 * sin 67 - 1/2 * 9.8 * (3)^2 = 187.78 - 44.1 = 143.7 ft.