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Alex777 [14]
4 years ago
5

Please help

Mathematics
1 answer:
nadezda [96]4 years ago
4 0
The answer A and D hope it right
You might be interested in
To frame two problems of linear equation in one variable of your choice and solve such that the result of the first problem shou
AVprozaik [17]

Answer:

x + y = 79 and

x - y = 25

(x,y) = (52,27)

Step-by-step explanation:

Let the variables be: x and y

The equations can be modelled as:

x + y = 79 and

x - y = 25

To solve for x and y, we have:

Make x the subject in x - y = 25

x = 25 + y

Substitute x = 25 + y in x + y = 79

25 + y + y = 79

25 + 2y = 79

Collect like terms

2y = 79 - 25

2y = 54

Divide both sides by 2

y = 27

Substitute y = 27 in x = 25 + y

x = 25 + 27

x = 52

So, we have:

(x,y) = (52,27)

8 0
3 years ago
Please only do 15 and 18 and pls explain.
Musya8 [376]
Nomber15:851-215=636
7 0
3 years ago
Read 2 more answers
How are you question
Sphinxa [80]

Answer:

good hbu

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Encuentren dos números cuyo cociente sea -1 y que la resta del primero menos el segundo sea -3/2
miskamm [114]

Answer:

\dfrac{3}{4}\ \text{and}\ \dfrac{-3}{4}

Step-by-step explanation:

Find two numbers whose quotient is -1 and the subtraction of the first minus the second is -3/2

Let two numbers are x and y. When they are divided the quotient is -1. So,

\dfrac{x}{y}=-1

It can also be written as :

x = -y ....(1)

The subtraction of first minus the second is -3/2 .

x-y=\dfrac{-3}{2}\ .....(2)

Use equation (1) in (2),

-y-y=\dfrac{-3}{2}\\\\-2y=\dfrac{-3}{2}\\\\y=\dfrac{3}{4}

From equation (1) : x=\dfrac{-3}{4}

Hence, two numbers are \dfrac{3}{4}\ \text{and}\ \dfrac{-3}{4}.

4 0
3 years ago
How do you solve for x
ivann1987 [24]
Clear out any fractions by Multiplying every term by the bottom parts. Add or Subtract the same value from both sides. Divide every term by the same nonzero value. Combine Like Terms. Factoring. Expanding (the opposite of factoring) may also help.
3 0
4 years ago
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