Find the point, Q, along the directed line segment AB that
1 answer:
Answer:
Point Q is at a distance of 4.7 units from A.
Step-by-step explanation:
From the graph, AC = 10 units and BC = 6 units. Applying the Pythagoras theorem,
=
+
= +
= 100 + 36
= 136
AB =
AB = 11.6619
AB = 11.66
≅ 11.7 units
But point Q divides AB into ratio 2:3. Therefore:
AQ = × AB
= × 11.66
= 4.664
AQ = 4.664
AQ ≅ 4.7 units
QB = × AB
= × 11.66
= 6.996
QB ≅ 7.0 units
So that point Q is at a distance of 4.7 units from A.
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Explanations:
- a. Each uppercase letter represents a point or angle of the triangle.
- b. Connect two points of a triangle and you get a line segment. The order of the letters does not matter. So AB is the same as BA.
- c. Like with part b, connecting two angles or points forms a segment.
- d. Note how the letter "A" is in both AB and CA, so this is the shared angle between the two segments.
- e. Sides AB, BC, and AC are all different lengths, so we have a scalene triangle. If you had two sides equal to each other, then you'd have an isosceles triangle. If all three sides are equal, then it would be equilateral.
There is no need for a diagram, but if you want, you can draw one out. See the attached image below for the diagram. This diagram should hopefully answer any questions you may have about the explanations above. There are many ways to draw the triangle, so your diagram might look different from mine.