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Anon25 [30]
3 years ago
11

Brainlist Tell me a joke, and you get brainlist

Mathematics
2 answers:
Lady_Fox [76]3 years ago
5 0

Answer:

Why did the chicken cross the road?

<em><u>To get to the other side</u></em>

mr_godi [17]3 years ago
4 0

Answer:

Gravity is an illusion.

Step-by-step explanation:

*floats* I HAVE ACHEIVED,,, C O M E D Y

pls brainlist tho

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Simon is doing a card trick using a standard 52 card deck. He shows his friend a card, replace it, and then shows his other frie
Elza [17]
It would be 39/50 then 13/50 sry I didn't have time to simplify it.

Hope this helps.
5 0
4 years ago
What is the answer<br><br> 10 x 57
Fofino [41]

Answer:

570 Mr.Monkay :D

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
the middle School golf team is selling golf balls to raise $850 for new equipment they sell golf balls for $2 each a case has 24
aniked [119]

Answer:

The number of cases of golf ball that team needed to raise money for equipment  is 3 .

Step-by-step explanation:

Given as :

The amount needed for new equipment = $850

The cost of each golf ball = $2

The number of packs of golf ball in each case = 24

The number of golf ball in each pack = 6

Let The number of cases of golf ball team needed to raise money for equipment = n cases

Now, According to question

∵ 1 pack has 6 balls

so, 24 pack has 6 × 24

i.e 24 packs has 144 balls

So, The number of balls in each case` = 144 balls

<u>Again</u>

∵ cost of 1 ball = $2

So, cost of 144 balls = $2 × 144

i.e cost of 144 balls in each case = $288

<u>Again</u>

∵ The amount needed for new equipment = $850

So, The number of cases of golf ball team needed to raise money for equipment = \dfrac{amount needed for new equipmen}{cost of 144 balls in each case }

Or, n = \dfrac{850}{288}

∴ n = 2.9 ≈ 3

So, The number of cases of golf ball that team needed to raise money for equipment  = n = 3

Hence, The number of cases of golf ball that team needed to raise money for equipment  is 3 . Answer

3 0
3 years ago
Which is the value of this expression when p=-2 and q=-1?
saul85 [17]

Answer:

D. 4

Step-by-step explanation:

[(p^2) (q^{-3}) ]^{-2}.[(p)^{-3}(q)^5] ^{-2}\\\\=[(p^2) (q^{-3}) \times(p)^{-3}(q)^5 ]^{-2}\\\\=[(p^{2}) \times(p)^{-3} \times (q^{-3}) \times(q)^5 ]^{-2}\\\\=[(p^{2-3}) \times (q^{5-3}) ]^{-2}\\\\=[(p^{-1}) \times (q^{2}) ]^{-2}\\\\=(p^{-1\times (-2)}) \times (q^{2\times (-2) }) \\\\=p^{2}\times q^{-4} \\\\= \frac{p^2}{q^4}\\\\= \frac{(-2)^2}{(-1)^4}\\\\= \frac{4}{1}\\\\= 4

8 0
3 years ago
The rectangle has an area of x square plus 15 square meters and a width of X plus 3
hammer [34]

Answer:

x + 5

Step-by-step explanation:

4 0
3 years ago
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