1 answer:
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By the divergence theorem, the surface integral given by
(where the integral is computed over the entire boundary of the surface) is equivalent to the triple integral
where
is the volume of the region 
bounded by 
.
You have
![\implies \nabla\cdot\mathbf F=\dfrac{\partial}{\partial x}[x^2y]+\dfrac{\partial}{\partial y}[xy^2]+\dfrac{\partial}{\partial z}[4xyz]=8xy](https://tex.z-dn.net/?f=%5Cimplies%20%5Cnabla%5Ccdot%5Cmathbf%20F%3D%5Cdfrac%7B%5Cpartial%7D%7B%5Cpartial%20x%7D%5Bx%5E2y%5D%2B%5Cdfrac%7B%5Cpartial%7D%7B%5Cpartial%20y%7D%5Bxy%5E2%5D%2B%5Cdfrac%7B%5Cpartial%7D%7B%5Cpartial%20z%7D%5B4xyz%5D%3D8xy)
and so the integral reduces to
(where the integral is computed over the entire boundary of the surface) is equivalent to the triple integral
where
You have
and so the integral reduces to
Answer:
E. 5
Step-by-step explanation:
Let's rewrite the equation in the form of y=mx+b, where m is the slope and b is the y-intercept (the value of y when x = 0).
2x + y = 5
y = -2x+5
M, the slope, is -2
<u>5, b, is the y-intercept</u>
See attached graph.
