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3 years ago

Area of parallelogram

Mathematics

2 answers:

Evgen [1.6K]3 years ago

6 0

Formula of a Area of Parallelogram

A = b x h

Aliun [14]3 years ago

5 0

The formula for the area of a parallelogram is base times height or bh.

There's a formula sheet on Khan Academy:
https://www.khanacademy.org/math/basic-geo/basic-geo-area-and-perimeter/parallelogram-area/a/area-of...

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A hypothesis will be used to test that a population mean equals 10 against the alternative that the population mean is less than

Nonamiya [84]

Answer:

Lets take the hypothesis

zα/2 

- zα/2 

Step-by-step explanation:

α/2 = 0.10/2 = 0.05 

z(0.05) = 3.92 

-z(0.05) = -3.92 

4 0

3 years ago

Can someone please help me

4vir4ik [10]

Answer:

Step-by-step explanation:

Two ways we can solve this problem:

1. Graphically

2. Mathematically

Because you already solved it graphically, I will show you how to do so mathematically. Of course, graphically is much much easier and more efficient in this problem.

Let's break the problem down.

First, we are given a graph which contains a slope.

To find slope, we use the technique -> rise/run

Picking 2 obvious points from the graph, we can see

1st point -> (10, 20)

2nd point -> (40, 80)

Now, let's find the slope

$\frac{80-20}{40-10} = \frac{60}{30} = 2$

Now, we have an equation y = 2x, where y = number of pies and x = cups of sugar

We want to find how many cups of sugar we need to bake 80 pies. Simply substitute 80 = number of pies = y

y = 2x -> 80 = 2x

Solving for x, divide both sides by 2

40 = x

We need 40 cups of sugar.

3 0

2 years ago

A House needs to some maintenance one sink is dripping water every 10 minutes and the other sink is dripping every 12 minutes if

e-lub [12.9K]

Answer:

60 minutes

Step-by-step explanation:

We solve this question using Lowest Common Factor method

Find and list multiples of each number of minutes( 12 and 10 minutes) until the first common multiple is found. This is the lowest common multiple.

Multiples of 10:

10, 20, 30, 40, 50, 60, 70, 80

Multiples of 12:

12, 24, 36, 48, 60, 72, 84

Therefore,

LCM(10, 12) = 60

The number if minutes until they both drip again is 60 minutes

7 0

3 years ago

Two payment options to rent a car: You can pay $20 a day plus 25¢ a mile (Option A) or pay $10 a day plus 50¢ a mile (Option B).

BaLLatris [955]

You must drive more than 40 miles to make option A the cheaper plan

Solution:

Two payment options to rent a car

Let "x" be the number of miles driven in one day

You can pay $20 a day plus 25¢ a mile (Option A)

25 cents is equal to 0.25 dollars

OPTION A : 20 + 0.25x

You pay $10 a day plus 50¢ a mile (Option B)

50 cents equal to 0.50 dollars

Option B: 10 + 0.50x

For what amount of daily miles will option A be the cheaper plan ?

For option A to be cheaper, Option A must be less than option B

Option A < Option B

$20 + 0.25x < 10 + 0.50x$

Solve the inequality

Add -0.50x on both sides

$20 +0.25x -0.50x < 10 + 0.50x - 0.50x\\\\20 - 0.25x < 10$

Add - 20 on both sides,

$20 - 0.25x - 20 < 10 - 20\\\\-0.25x < -10$

$\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}$

$0.25x > 10$

Divide both sides by 0.25

$x > 40$

Thus you must drive more than 40 miles to make option A the cheaper plan

7 0

3 years ago

Find the area of following rhombuses. Round your answers to the nearest tenth if necessary.

polet [3.4K]

Answer:

$Area =55.4ft^2$

Step-by-step explanation:

Given

The attached rhombus

Required

The area

First, calculate the length of half the vertical diagonal (x).

Length x is represented as the adjacent to 60 degrees

So, we have:

$\tan(60) = \frac{4\sqrt 3}{x}$

Solve for x

$x = \frac{4\sqrt 3}{\tan(60)}$

$\tan(60) = \sqrt 3$

So:

$x = \frac{4\sqrt 3}{\sqrt 3}$

$x = 4$

At this point, we have established that the rhombus is made up 4 triangles of the following dimensions

$Base = 4\sqrt 3$

$Height = 4$

So, the area of the rhombus is 4 times the area of 1 triangle

$Area = 4 * \frac{1}{2} * Base * Height$

$Area = 4 * \frac{1}{2} * 4\sqrt 3 * 4$

$Area =2 * 4\sqrt 3 * 4$

$Area =55.4ft^2$

7 0

3 years ago