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lara31 [8.8K]
3 years ago
15

the volume of a rectangular prism can be computed using the formula V=lwh what is the width of a prism that has a volume of 240

cubic cubic centimeters a length of 10 centimeters and a height of 6 centimeters
Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
6 0
The width would be 4 centimeters
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Hector has $590 in his account. He earned $15 per hour for x hours. Jeremy has $545 in his account. He earned $20 per hour for x
Nutka1998 [239]

Answer:

equation = 590 + 15x = 545 + 20x

No. of hours worked = 9

Step-by-step explanation:

Given that both worked for same number of hours

and

Jeremy worked for for x hours

it meant that Hector also worked for x hours(it is also mentioned same in the problem)

now that we know the number of hours worked in form of x

lets find

total money in their account if they worked for x hours

___________________________________________

For Hector

Money in Hector's account = $590

Earning for Hector in 1 hour = $15

Earning for Hector in x hour = x*Earning for Hector in 1 hour = $15x

Total money in with Hector after x hours of work

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Similarly

For Jeremy

Money in Jeremys account = $545

Earning for Jeremy in 1 hour = $20

Earning for Jeremy in x hour = x*Earning for Jeremy in 1 hour = $20x

Total money in with Jeremy after x hours of work

 = Money in Jeremy's account + Earning for Jeremy in x hour = $545 + $20x

Given that they same amount of money

thus

$590 + $15x = $545 + $20x

$sign gets cancelled from both sides

590 + 15x = 545 + 20x  Thus, we got the required equation  

=> 590 - 545 = 20x - 15x

=> 45 = 5x

=> x = 45/5 = 9

Thus, both of them worked for 9 hours

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3 years ago
If and , find .<br><br> A. <br> B. <br> C. <br> D.
trapecia [35]
Answer: option D. 2x^2 + (3/2)x  - 5

Explanation:

1) polynomials given:

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2) question: find (f + g) (x)

That means that f(x) + g(x), so you have to add up the two polynomials given.

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b) terms with x: x/2 + x

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c) constant terms: - 2 + (-3) = - 2 - 3 = - 5

5) Result: 2x^2 + (3/2)x - 5

That is the option d.


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