All categories

4 years ago

a certain forest covers an area of 4100km squared. if each year the area decreased by 4.5% what will be the area after 15 years

Mathematics

1 answer:

babunello [35]4 years ago

8 0

Answer:

2055 km²

Step-by-step explanation:

The amount of forest remaining after t years can be modeled by the exponential equation ...

remaining = original · (multiplier each year)^(number of years)

area = 4100·0.955^t

Then for t=15, the area is ...

area = 4100·0.955^15 ≈ 2055.1 . . . . km²

The area of the forest after 15 years will be about 2055 square kilometers.

You might be interested in

Find the surface area of the composite solid. Leave your answer in terms of pi.

bonufazy [111]

Total surface area = lateral area of cone + lateral area of cylinder + area of base of cylinder:
cone: πrL = π(5cm)(13cm) = 65πcm²
cylinder: 2πrh = 2π(5cm)(12cm) = 120πcm²
base: πr² = π(5cm)² = 25πcm²
total surface area = 65πcm² + 120πcm² + 25πcm² = 210πcm²

4 0

3 years ago

Lara planted some seeds. For every 3 seeds Lara planted, only 2 seeds grew. Altogether, 12 seeds grew. How many seeds did Lara p

miss Akunina [59]

18 seeds!! hope this helps.

5 0

3 years ago

Read 2 more answers

Solve these problems and show your work! ONLY HAND WRITTEN answers will be accepted! When

Dahasolnce [82]

For Kohl’s:

Purchase Price:

$60

Discount:

(60 x 25)/100 = $15.00

Final Price:

60 - 15.00 = $45.00

You would save $15.00 from Kohl’s and pay only $45.00

For Target:

Purchase Price:

$38

Discount:

(38 x 15)/100 = $5.70

Final Price:

38 - 5.70 = $32.30

You would save $5.70 from Target and pay only $32.30

Hope this helps! :)

3 0

4 years ago

If a certain cannon is fired from a height of 8.8 meters above the ground, at a certain angle, the height of the cannonball ab

Dennis_Churaev [7]

Answer:

It would take approximately 6.50 second for the cannonball to strike the ground.

Step-by-step explanation:

Consider the provided function.

$h(t)=-4.9t^2+30.5t+8.8$

We need to find the time takes for the cannonball to strike the ground.

Substitute h(t) = 0 in above function.

$-4.9t^2+30.5t+8.8=0$

Multiply both sides by 10.

$-49t^2+305t+88=0$

For a quadratic equation of the form $ax^2+bx+c=0$ the solutions are: $x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Substitute a = -49, b = 305 and c=88

$t=\frac{-305+\sqrt{305^2-4\left(-49\right)88}}{2\left(-49\right)}=-\frac{-305+\sqrt{110273}}{98}\\t = \frac{-305-\sqrt{305^2-4\left(-49\right)88}}{2\left(-49\right)}= \frac{305+\sqrt{110273}}{98}$

Ignore the negative value of t as time can't be a negative number.

Thus,

$t=\frac{305+\sqrt{110273}}{98}\approx6.50$

Hence, it would take approximately 6.50 second for the cannonball to strike the ground.

6 0

3 years ago

Dilating a triangle changes the shape of the triangle but does not change its size. A. True B. False

Lorico [155]

False, dilation changes the base and height of the triangle, forcing the area to change as well.

5 0

3 years ago

Read 2 more answers