3 years ago

Please help with this!!

Mathematics

1 answer:

Mumz [18]3 years ago

3 0

Answer:

2x + 4

Step-by-step explanation:

So sorry if this is wrong, I'm rusty in this area of math

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Helppppppp will give the brainiest if correct !!!

MissTica

Answer:

Step-by-step explanation:

$7-3x-4+x\qquad\text{combine like terms}\\\\=(-3x+1x) + (7-4)\\\\=-2x+3=3-2x$

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If 7a=3 and 3b=7 what is the value of a/b

Luba_88 [7]

A=3/7 b=4....................

8 0

3 years ago

16x^7 - 8x^3 / 4x^3

Sunny_sXe [5.5K]

Answer:

4x^4-2

Step-by-step explanation:

$\dfrac{16x^7-8x^3}{4x^3}= \\\\\\\dfrac{4x^3(4x^4-2)}{4x^3}= \\\\\\4x^4-2$

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3 years ago

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there are 38 cars parked in the parking struture the parking structure is not full to capacity.there 13 parking space that are e

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3 years ago

Which of the equations are true identities? a. (3x-2y)(2y-3x)=9x^2-4y^2 b. (2k+5r)(2k-5r)=4k^2-25r^2

krok68 [10]

Answer:

b. $(2k+5r)(2k-5r)$

Step-by-step explanation:

We have to find the equation which are true identity.

a. $(3-2y)(2y-3x)$

$(3x-2y)(2y-3x)=3x(2y-3x)-2y(2y-3x)$

$=6xy-9x^2-4y^2+6xy$

$(3-2y)(2y-3x)\neq 9x^2-4y^2$

b. $(2k+5r)(2k-5r)$

$(2k)^2-(5r)^2$

Using identity

$(a+b)(a-b)=a^2-b^2$

$4k^2-25r^2$

It is true.

Hence, option b is true.

7 0

3 years ago