This is a typical radioactive decay problem which uses the general form:
A = A0e^(-kt)
So, in the given equation, A0 = 192 and k = 0.015. We are to find the amount of substance left after t = 55 years. That would be represented by A. The solution is as follows:
A = 192e^(-0.015*55)
<em>A = 84 mg</em>
Answer:
-4
Step-by-step explanation:
y=3x - 1 x= -1
y = 3(-1) -1
y = -3 -1
y= -4
Answer:
The daily rate is: 17500 units per day
Step-by-step explanation:
Given
Required
Find when
We have:
Differentiate both sides with respect to time
Factorize
Substitute: and
Answer:
b i think
Step-by-step explanation:
i hope this helps