Y=mx+b
m=slope
b=yintercept
slope=(y1-y2)/(x1-x2)
(x,y)
x1=6
y1=-4
x2=-6
y2=2
(-4-2)/(6-(-6))=-6/12=-1/2
y=-1/2x+b
subsitute one point
(6,-4)
x=6
y=-4
-4=1/2(6)+b
-4=3+b
subtract 3
-7=b
y=-1/2x-7 is answer
Answer:
The second band
Step-by-step explanation:
50+20=70
20+25=45
Answer:
The last option
Step-by-step explanation:
This definitely isn't a parallelogram, so you can knock both of the yes answers out. One of the rules of parallelograms are that if there is 1 right angle then all four need to be right angles, even if the others are supplementary if the right angle rule is not followed then the shape is not a parallelogram.
Let's buils the intersection plane:
Point P is on AB and AP=2, then PB=3; point Q is on AE and AQ=1, then QE=4. Let P' be a point on CD such that CP'=2 and Q' be a point on the plane CDHG such that P'Q'=1 and P'Q' is perpendicular to CD. The line CQ' intersects HD at point R and the plane CPQR is intersection plane.
Consider triangles ΔCDR and ΔCP'Q', they are similar. So,

,
so R is a midlepoint of the side HD (for details see picture).