A = √(15²-9²) = √(225-81) = √144 = 12
Replace each "x" in the original equation with (4):
3(4)^2 + 2(4) - 5
= 3(16) + 8 - 5 = 48 + 8 - 5. Can you finish this?
Answer:
The answer is ten or Letter C
Step-by-step explanation:
You plug in the values of w and x so you get 3(1/4*8)+4. Multiply whats in the parthensis then distribute the 3 into 2 and get 6. So 6+4=10. Thats the answer for this expression. I hope this helps!
Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
Area = (1/2)(AB + AB/4)·h = (5/8)AB·h
The given dimensions let us determine the area of ∆BCE to be
Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²
The total area of the trapezoid is also the sum of the areas ...
Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h
Putting all of the above into the equation for the total area of the trapezoid, we have
Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
(5/8 -1/6 -1/12)AB·h = 30 cm²
AB·h = (30 cm²)/(3/8) = 80 cm²
Then the area of the trapezoid is
Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²
Answer:
-30
Step-by-step explanation:
-4b^6 + -24b^6 = -30b^6
