2 years ago

It's A Factor Problem (Can You Show Me The Steps) And Not Just Give Me The Answer.

1 answer:

3 0

28.) 8x + 28 - 16y
Find the GCF (greater common factor) or the smallest number that divide
8, 28 and 16 ALLTOGETHER.

8 = 2 x 4
28 = 7 x 4
16 = 4 x 4, so 4 is the GCF: Now you take 4 as a common factor

4(2x + 7 + 4y)

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How many ways can an employer send 3 employees to a job fair if she has 11 employees?

algol13

We have to find the number of ways an employer send 3 employees to a job fair if she has 11 employees.

This is the problem from combination.

The formula for combination is given by

$^nC_r= \frac{n!}{r!(n-r)!}$

Here, n= 11, r= 3

Therefore, total number of ways is given by

$^{11}C_3= \frac{11!}{3!(11-3)!}\\
\\
=\frac{11!}{3!8!}\\
\\
=\frac{8!\times 9 \times 10 \times 11}{3!8!}\\
\\
=\frac{9 \times 10 \times 11}{6}\\
\\
=165$