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Nostrana [21]
2 years ago
14

. . . , , ,help please ​

Mathematics
1 answer:
IgorC [24]2 years ago
3 0

The system of inequalities of the graph is (a) y > x² + 2x - 3 and y > 2x + 3

<h3>How to determine the inequalities?</h3>

The complete question requires that we determine the system of inequalities of the graph (the graph is attached)

Going by the list of options, the equation of the quadratic curve is:

y = x² + 2x - 3

From the graph, we can see that:

  • The curve uses a dotted line
  • The upper part is shaded

The above means that the inequality is greater than i.e. >

So, we have:

y > x² + 2x - 3

The above eliminates options (b) and (c)

From the graph, we can see that the straight line has a positive slope, a dotted line and the upper part is shaded.

The linear inequality in option (a) has the above characteristics.

So, the inequality is:

y > 2x + 3

Hence, the system of inequalities of the graph is (a) y > x² + 2x - 3 and y > 2x + 3

Read more about inequalities at:

brainly.com/question/25275758

#SPJ1

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The first terms of a geometric sequence are as follows.
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The fourth and fifth term of this sequence is -30 and -10 respectively.

Data;

  • first term (a) = -810
  • common difference (r) = ?

<h3>Common Difference</h3>

The common difference in a geometric progression is the ratio between two successive terms.

Let's find the common difference in this sequence

r = \frac{-270}{-810} \\r = \frac{1}{3}

The nth term of a geometric sequence is given as

T_n = ar^n^-^1\\

The next two terms of this sequence will be 4th and 5th term.

The fourth term of this sequence is

T_4 = ar^4^-^1\\T_4 = -810 * (\frac{1}{3})^3\\ T_4 = -810 * \frac{1}{27}\\ T_4 = -30

The fifth term of this sequence is

T_5 = ar^5^-^1\\T_5 = -810 * (\frac{1}{3})^4\\T_5 = -810 * \frac{1}{81} \\T_5 = -10

The fourth and fifth term of this sequence is -30 and -10 respectively.

Learn more on geometric progression here;

brainly.com/question/12006112

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