Help answer my question
1 answer:
You might be interested in
Answer:
0.7385 = 73.85% probability that it is indeed a sample of copied work.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Identified as a copy
Event B: Is a copy
Probability of being identified as a copy:
80% of 15%(copy)
100 - 95 = 5% of 100 - 15 = 85%(not a copy). So
Probability of being identified as a copy and being a copy.
80% of 15%. So
What is the probability that it is indeed a sample of copied work?
0.7385 = 73.85% probability that it is indeed a sample of copied work.
Answer:
Option d
Step-by-step explanation:
Given that television networks frequently run public opinion polls on issues of concern. One network conducted a scientific poll asking a question concerning the approval rating of the way President Obama was handling the Iraq War. At about the same time a second network ran an online poll using a very similar question.
Observed data is
Poll Scien Online total
approve 339 385 724
disapprove 780 573 1363
1119 958 2087
(Two tailed chi square test)
Let us find out expected and chi square
Expected = row total x column total/grand total
The cell count expected in the online poll for those who approve
=
chi square = 7.81
Hence option d is right.