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Thepotemich [5.8K]
3 years ago
7

Determine whether or not the set is well defined. (x l x is an expensive boat on the Great Lakes)

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
8 0
A, well defined.

Hope this helps!
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8 0
3 years ago
Solve this inequality: 3p – 6 > 21.
Wittaler [7]
<span>To solve for p:
3p – 6 > 21
</span><span>3p - 6 + 6 > 21 + 6 (add 6 to both sides)
</span><span>3p > 27
3p/3 </span><span>> 27/3 (divide both sides by 3 to get p by itself)
</span><span>p > 9</span>
4 0
4 years ago
2^x=3^x+1 what are the exact approximate solutions
Mashcka [7]

Answer:

d.

Step-by-step explanation:

The goal of course is to solve for x.  Right now there are 2 of them, one on each side of the equals sign, and they are both in exponential positions.  We have to get them out of that position.  The way we do that is by taking the natural log of both sides.  The power rule then says we can move the exponents down in front.

ln(2^x)=ln(3^{x+1}) becomes, after following the power rule:

x ln(2) = (x + 1) ln(3).  We will distribute on the right side to get

x ln(2) = x ln(3) + 1 ln(3).  The goal is to solve for x, so we will get both of them on the same side:

x ln(2) - x ln(3) = ln(3).  We can now factor out the common x on the left to get:

x(ln2 - ln3) = ln3.  The rule that "undoes" that division is the quotient rule backwards.  Before that was a subtraction problem it was a division, so we put it back that way and get:

x(\frac{ln(2)}{ln(3)})=ln(3).  We can factor out the ln from the left to simplify a bit:

x[ln(\frac{2}{3})]=ln(3).  Divide both sides by ln(2/3) to get the x all alone:

x=\frac{ln(3)}{ln(\frac{2}{3}) }

On your calculator, you will find that this is approximately -2.709

6 0
3 years ago
HELP PLEASE TELL ME WHICH ONE WITH AN EXPLAINATION
Alex787 [66]

Answer:

Im not sure, but i think it's the bottom because there not working with negatives

Step-by-step explanation:

Don't put that as the answer tho, im not too sure.

6 0
3 years ago
Read 2 more answers
One positive integer is 5 times another positive integer and their product is 320. What are the positive integers?​
NeTakaya
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
x = 5y
xy = 320

Substitute the first equation into the second equation
(5y)(y) = 320
5y^2 = 320
y^2 = 64
y = 8 (y must be positive)

The integers are (x, y) = (40, 8).
7 0
3 years ago
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