<u>The equation that shows the decomposition of silver carbonate are;</u>
2Ag2CO3 ---------> 4Ag + 2CO2 + O2
<u>From the periodic table:</u>
Mass of silver = 107.8682 grams
Mass of carbon = 12 grams
Mass of oxygen = 16 grams
Molar mass of Ag2CO3 = 2(107.8682) + 12 + 3(16) = 275.7364 grams
<u>From the balanced equation above:</u>
2(275.7362) = 551.4728 grams<em> of</em> Ag2CO3 <em>produces</em> 4(107.8682) = 431.4728 <em>grams of Ag</em>
<u>Thus, in order to know the mass of Ag produced from 2.76 grams of Ag2CO3, we'll use the cross multiplication method; </u>
Mass of Ag produced = (2.76 × 431.4728) / (551.4728) = <em>2.16 grams</em>
Based on the calculations demonstrated above, the law of conservation of mass is applied.