Question

LAST ONE!!!

Answer 1

The equation that shows the decomposition of silver carbonate are;

2Ag2CO3 ---------> 4Ag + 2CO2 + O2

From the periodic table:

Mass of silver = 107.8682 grams

Mass of carbon = 12 grams

Mass of oxygen = 16 grams

Molar mass of Ag2CO3 = 2(107.8682) + 12 + 3(16) = 275.7364 grams

From the balanced equation above:

2(275.7362) = 551.4728 grams of Ag2CO3 produces 4(107.8682) = 431.4728 grams of Ag

Thus, in order to know the mass of Ag produced from 2.76 grams of Ag2CO3, we'll use the cross multiplication method;

Mass of Ag produced = (2.76 × 431.4728) / (551.4728) = 2.16 grams

Based on the calculations demonstrated above, the law of conservation of mass is applied.