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Minchanka [31]
3 years ago
8

What did the scout say after fixing the little old lady's bicycle horn

Mathematics
1 answer:
Elodia [21]3 years ago
8 0
Did he say your welcome?
 
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2) A big league pitching coach tries to limit his pitchers to 110
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P is less than or equal to (<) 110-52 you want to use the < sign with a line under it. The minus 52 is because he has already thrown 52 out of his 110 and P is how many pitches he is alloted
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3 years ago
Choices: A) 7 B) 12 C) 9 D) 6<br>Please help!!
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There are 9 possible combinations, because you can have 3 main dishes, and each of thise have 3 side dishes that can go with them. I hope this helps! Could I possibly get brainliest.

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4 years ago
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How do you convert gallons into ounces
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Multiply number of gallons by 16 (because 16 oz/ 1 gallon).
7 0
3 years ago
If f(x) = 9x10 tan−1x, find f '(x).
djverab [1.8K]

Answer:

\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:                                                           \displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)  

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]:                                                                             \displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = 9x^{10} \tan^{-1}(x)

<u>Step 2: Differentiate</u>

  1. [Function] Derivative Rule [Product Rule]:                                                   \displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  2. Rewrite [Derivative Property - Multiplied Constant]:                                  \displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  3. Basic Power Rule:                                                                                         \displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  4. Arctrig Derivative:                                                                                         \displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0
3 years ago
The original quantity is 10 and the new quantity is 13. What is the percent change?​
Leya [2.2K]

3 is 13 more than 10, and 3 is 30% of 10, so 30% im pretty sure

6 0
3 years ago
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