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Minchanka [31]
3 years ago
8

What did the scout say after fixing the little old lady's bicycle horn

Mathematics
1 answer:
Elodia [21]3 years ago
8 0
Did he say your welcome?
 
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I need to know, the area of sector AOB is what fractional part of the area of circle O
sertanlavr [38]

We are given that triangle AOB

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1 year ago
C(x)=4x-2 and d(x)=x^(2)+5, what is (c*d)(x)
lawyer [7]

Answer:4x^3-2x^2+20x-10

Step-by-step explanation:

5 0
3 years ago
Need Help Please!!!!!!!
marshall27 [118]

ANSWER

$1,413.81

EXPLANATION

The compound interest formula is given by:

A=P(1+r\%)^t

Where P=900 is the balance in the account, t=10 is the number of years and r=0.0462 is the rate.

We substitute the values in to the formula to get:

A=900(1+4.62\%)^{10}

A=900(1.0462)^{10}

This simplifies to:

A=1413.81

Therefore $1413.81 will be in the account after 10 years.

6 0
3 years ago
Read 2 more answers
A metal rod will be cut into pieces that are each 1/56 meters long. The rod is 7/8 meters long. How many pieces will be made fro
S_A_V [24]

The number of pieces made from rod is 49

<h3><u>Solution:</u></h3>

Given that A metal rod will be cut into pieces that are each 1/56 meters long

The rod is 7/8 meters long.

<em><u>To find: number of peices made from rod</u></em>

The number of peices made from rod can be calculated by dividing the total length of rod by length of each piece

\text {number of pieces made }=\frac{\text {total length of rod }}{\text { length of each piece}}

Here total length of rod = \frac{7}{8} meters

length of each piece to be made = \frac{1}{56} meters

Substituting the values in above formula, we get

\text {number of pieces made }=\frac{\frac{7}{8}}{\frac{1}{56}}=\frac{7}{8} \times \frac{56}{1}

\text {number of pieces made }=7 \times 7=49

So the number of pieces made from rod is 49

7 0
3 years ago
Given ACM, angle C=90º. AP=9, PM=12. Find AC, CM, AM.
Gnesinka [82]

Answer:

AM = 25, AC = 15, CM = 20

Step-by-step explanation:

The given parameters are;

In ΔACM, ∠C = 90°, \overline{CP} ⊥ \overline{AM}, AP = 9, and PM = 16

\overline{AC}² + \overline{CM}² = \overline{AM}²

\overline{AM} = \overline{AP} + PM = 9 + 16 = 25

\overline{AM} = 25

\overline{AC}² = \overline{AP}² + \overline{CP}² = 9² +  \overline{CP}²

∴ \overline{AC}² = 9² +  \overline{CP}²

Similarly we get;

\overline{CM}² = 16² + \overline{CP}²

Therefore, we get;

\overline{AC}² + \overline{CM}² = 9² +  \overline{CP}² + 16² + \overline{CP}² = \overline{AM}² = 25²

2·\overline{CP}² = 25² - (9² + 16²) = 288

\overline{CP}² = 288/2 = 144

\overline{CP} = √144 = 12

From \overline{AC}² = 9² +  \overline{CP}², we get

\overline{AC} = √(9² +  12²) = 15

\overline{AC} = 15

From, \overline{CM}² = 16² + \overline{CP}², we get;

\overline{CM} = √(16² + 12²) = 20

\overline{CM} = 20.

3 0
3 years ago
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