I hope this helps you understand how to do the problem.
Answer:
The time of a commercial airplane is 280 minutes
Step-by-step explanation:
Let
x -----> the speed of a commercial airplane
y ----> the speed of a jet plane
t -----> the time that a jet airplane takes from Vancouver to Regina
we know that
The speed is equal to divide the distance by the time
y=2x ----> equation A
<u><em>The speed of a commercial airplane is equal to</em></u>
x=1,730/(t+140) ----> equation B
<u><em>The speed of a jet airplane is equal to</em></u>
y=1,730/t -----> equation C
substitute equation B and equation C in equation A
1,730/t=2(1,730/(t+140))
Solve for t
1/t=(2/(t+140))
t+140=2t
2t-t=140
t=140 minutes
therefore
The time of a commercial airplane is
t+140=140+140=280 minutes
Answer: (9,18)
Step-by-step explanation: Graph it mark your midpoint and see the difference between them and do it on the opposite sirrection and you should get it
Answer:
y=-5*x+5
Step-by-step explanation:
the critical point are (5,0) and (0,1). the equation of the system is y=a*x+b. you substite y as 5 and 0 and x as 0 and 1 and you get it
Answer:
Step-by-step explanation:
so its 36+9 = 45
36/45=4/5
