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Nimfa-mama [501]
3 years ago
13

Can someone please help me with math for college readiness

Mathematics
2 answers:
frez [133]3 years ago
8 0
It is best to start by converting all to decimals. so 7 5/6= 7.8333 and 31/4=7.75
o in order of least to greatest it is 6.79, 7.729, 31/4, 7 5/6.
bixtya [17]3 years ago
6 0
6.79,7.729,31/4,7+5/6
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Y=3x+4 y=-2x-1 mathaaaaa
valentinak56 [21]

Answer:

the answer is x=−1 and y=1

Step-by-step explanation:

hoped I helped:)

7 0
2 years ago
The population of a town doubled every 5 years from 1960 to 1975. What is the percentage increase in population in this period ?
777dan777 [17]

Answer:

<h2>800%</h2>

Step-by-step explanation:

Let p represent the population

in 1965 → the population becomes 2p

in 1970 → the population becomes 2(2p) = 4p

in 1975 → the population becomes 2(4p) = 8p

 p  ——————> 100%

8p  ————-—-> x%

then

x=\frac{8p*100}{p}=800

5 0
3 years ago
A boat is 75 miles west and 60 miles north from the nearest port. What bearing should be taken to sail directly to port? S 39° E
Nimfa-mama [501]
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7 0
3 years ago
Need this answered today, will give brainliest: The Steelers are on the Cowboys’ fifteen-yard line. Use your place value mat or
Nata [24]

Answer: 15 yards

Step-by-step explanation:

From the question, we have been informed that the Steelers are on the Cowboys' fifteen-yard line. Using the place value mat to calculate how much farther Steelers need to travel to score a touchdown goes thus:

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5 0
3 years ago
Consider the functions f and g defined by \[f(x) = \sqrt{\dfrac{x+1}{x-1}}\qquad\qquad\text{and}\qquad\qquad g(x) = \dfrac{\sqrt
tino4ka555 [31]

Answer:

The given functions are not same because the domain of both functions are different.

Step-by-step explanation:

The given functions are

f(x)= \sqrt{\dfrac{x+1}{x-1}}

g(x) = \dfrac{\sqrt{x+1}}{\sqrt{x-1}}

First find the domain of both functions. Radicand can not be negative.

Domain of f(x):

\dfrac{x+1}{x-1}>0

This is possible if both numerator or denominator are either positive or negative.

Case 1: Both numerator or denominator are positive.

x+1\geq 0\Rightarrow x\geq -1

x-1\geq 0\Rightarrow x\geq 1

So, the function is defined for x≥1.

Case 2: Both numerator or denominator are negative.

x+1\leq 0\Rightarrow x\leq -1

x-1\leq 0\Rightarrow x\leq 1

So, the function is defined for x≤-1.

From case 1 and 2 the domain of the function f(x) is (-∞,-1]∪[1,∞).

Domain of g(x):

x+1\geq 0\Rightarrow x\geq -1

x-1\geq 0\Rightarrow x\geq 1

So, the function is defined for x≥1.

So, domain of g(x) is [1,∞).

Therefore, the given functions are not same because the domain of both functions are different.

4 0
3 years ago
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