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Dmitry_Shevchenko [17]
3 years ago
5

If tan f° = two over one and the measure of segment YW is 8 units, what is the measure of segment XW? triangle XYW in which angl

e W is a right angle, angle X measure f degrees, and angle Y measures d degrees 2 units 4 units 7 units 8 units
Mathematics
2 answers:
AnnyKZ [126]3 years ago
5 0

Answer:

4 units

Step-by-step explanation:

i took the test and i got it correct

AVprozaik [17]3 years ago
4 0

Answer:

4 units

Step-by-step explanation:

just took the test and it was right

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80 mph

Step-by-step explanation:

720÷9=80

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(3,4) and (12,19) find the equation of the line that passes through it
harina [27]

Answer:

The equation of the line will be:

y=\frac{5}{3}x-1

Step-by-step explanation:

Given the points

  • (3, 4)
  • (12, 9)

Finding the slope between (3, 4) and (12, 9)

\left(x_1,\:y_1\right)=\left(3,\:4\right),\:\left(x_2,\:y_2\right)=\left(12,\:19\right)

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

m=\frac{19-4}{12-3}

m=\frac{5}{3}

The equation of the line can be obtained using the point-slope form of the equation of the line

y-y_1=m\left(x-x_1\right)

substituting the values m = 5/9 and the point (3, 4)

y-4=\frac{5}{3}\left(x-3\right)

y-4+4=\frac{5}{3}\left(x-3\right)+4

y=\frac{5}{3}x-1

Therefore, the equation of the line will be:

y=\frac{5}{3}x-1

5 0
3 years ago
How many terms are there in the sequence 1, 8, 28, 56, ..., 1 ?
BabaBlast [244]

Answer:

9 terms

Step-by-step explanation:

Given:  

1, 8, 28, 56, ..., 1

Required

Determine the number of sequence

To determine the number of sequence, we need to understand how the sequence are generated

The sequence are generated using

\left[\begin{array}{c}n&&r\end{array}\right] = \frac{n!}{(n-r)!r!}

Where n = 8 and r = 0,1....8

When r = 0

\left[\begin{array}{c}8&&0\end{array}\right] = \frac{8!}{(8-0)!0!} = \frac{8!}{8!0!} = 1

When r = 1

\left[\begin{array}{c}8&&1\end{array}\right] = \frac{8!}{(8-1)!1!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8

When r = 2

\left[\begin{array}{c}8&&2\end{array}\right] = \frac{8!}{(8-2)!2!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} =2 8

When r = 3

\left[\begin{array}{c}8&&3\end{array}\right] = \frac{8!}{(8-3)!3!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56

When r = 4

\left[\begin{array}{c}8&&4\end{array}\right] = \frac{8!}{(8-4)!4!} = \frac{8!}{4!3!} = \frac{8 * 7 * 6 * 5 * 4!}{4! *4*3* 2 *1} = \frac{8 * 7 * 6*5}{4*3 *2 *1} = 70

When r = 5

\left[\begin{array}{c}8&&5\end{array}\right] = \frac{8!}{(8-5)!5!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56

When r = 6

\left[\begin{array}{c}8&&6\end{array}\right] = \frac{8!}{(8-6)!6!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} = 28

When r = 7

\left[\begin{array}{c}8&&7\end{array}\right] = \frac{8!}{(8-7)!7!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8

When r = 8

\left[\begin{array}{c}8&&8\end{array}\right] = \frac{8!}{(8-8)!8!} = \frac{8!}{8!0!} = 1

The full sequence is: 1,8,28,56,70,56,28,8,1

And the number of terms is 9

3 0
3 years ago
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