If you were to use the substitution method to solve the following system write the new equation after the expression equilavent
to x from the first equation is substituted into the second equation x+y=6 3×-y=6
1 answer:
Subtract y from the fist equation to get an expression for x.
... x + y - y = 6 - y
... x = 6 - y
Assuming your multiplication symbol (×) in the second equation is supposed to be the variable x, performing the substitution gives
... 3(6-y) - y = 6 . . . . . . equation after substitution
... 18 - 4y = 6 . . . . . . . . eliminate parentheses
... 12 - 4y = 0 . . . . . . . . subtract 6
... 3 - y = 0 . . . . . . . . . . divide by 4
... 3 = y . . . . . . . . . . . . .add y
Now, we can use the above expression for x to find x
... x = 6 - y = 6 - 3
... x = 3
The solution of the system of equations is (x, y) = (3, 3).
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